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Posted: 6/9/2013 5:05:53 PM EDT
total energy for a 2kg falling rock is 5000 joules. If its potential energy is 1975 joules, what is its kinetic energy?

I know that I need the formula of weight x hieght to get the potential energy. I also know the kinetic energy requires 1/2 mass x speed^2

How in the hell do I solve this? We are skipping around in the book and I am fucking lost.
Link Posted: 6/9/2013 7:16:04 PM EDT
[#1]
I haven't looked at this stuff for maybe 40 years, so I could be wrong, but isn't the sum of the object's potential energy and kinetic energy a constant?


Link Posted: 6/9/2013 8:43:37 PM EDT
[#2]
Total energy is potential + kinetic
Total energy remains constant. Before motion (at Max h), total is all potential.
H turns into a, so at h=0, total is all kinetic
Link Posted: 6/10/2013 12:09:35 AM EDT
[#3]
If I understand the question correctly you have a 2kg falling rock, and at a single instant in time you know that the total energy is 5000J and the potential energy is 1975J.

Total energy = kinetic + potential
5000J = kinetic + 1975J
5000J - 1975J = kinetic
3025J = kinetic

Link Posted: 6/10/2013 12:15:36 AM EDT
[#4]
Total E= KE + PE
5000=KE+1975
KE=3025

(1/2)mv^2=KE
(1/2)(2)V^2=3025
V=55 m/s

PE=MGH
1975=2(9.8)H
H=100.765 meters
Link Posted: 6/10/2013 12:41:45 AM EDT
[#5]
Quoted:
Total E= KE + PE
5000=KE+1975
KE=3025

(1/2)mv^2=KE
(1/2)(2)V^2=3025
V=55 m/s


PE=MGH
1975=2(9.8)H
H=100.765 meters


That is what I ended up with. I knew I had seen total energy somewhere but I couldnt find it. When I got the square root of 3025 I knew I must be close.

Thanks!

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