And if so, where does the pressure go?
This relates to my thread abotu a squib yesterday:
www.ar15.com/forums/topic.html?b=3&f=118&t=264024I could have sworn that the rifle cycled, and I noticed the problem when the next round wouldn't chamber proberly (because the squib was only a very short distance into the barrel). But a number of people correctly pointed out that the rifle COULD NOT have cycled if the bullet didn't make it past the gas port (which it obviously didn't), and that I must simply be remembering the sequence of events wrong. Which is entirely likely, since my memory is atrocious
. I'm starting to think that perhaps the squib was so weak that it maybe just sounded like a misfire (i.e., just a click of the hammer dropping), making me think that the previous cartridge had failed to eject - and manually operating the handle and trying to chamber the next round. (As an aside, if a cartridge had no powder in it, only the primer - would that be enough to force the bullet a quarter of an inch or so into the bore? and might you not even hear the sound of the primer?)
That may be what happend, but it made me wonder about the following scenario:
What if you had a reduced load, that had enough power to force the bullet ALMOST all the way to the gas port, but not quite - stopping right before the gas port.
Is there no way that the rifle would cycle? I'm guessing no, since the gas pressure is required to unlock the bolt, right? Or is there a way?
If not, does the gas pressure just "sit" in the barrel until the shooter extracts the round by manually pulling the bolt back? Or would it seep out through the rifling, around the bullet, or something?
Just a matter of curiosity, and the operation of the AR - not really important. But I know it's a question that the experts at ar15.com can easilt answer.