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Posted: 12/27/2012 5:52:36 PM EDT
[Last Edit: 12/27/2012 6:39:37 PM EDT by notrega]
Explain this...



or this...

How is this??

Dad: Playing a record? I'll show you something interesting. Compare a point on the label with a point on the record's outer edge. They both make a completed circle in the same amount of time, right?
Calvin: Yeah...
Dad: But the point on the record's edge has to make a bigger circle in the same time, so it goes faster. See, two points at two speeds even though they both make the same revolutions per minute!

Link Posted: 12/27/2012 5:54:05 PM EDT
Originally Posted By notrega:
Explain this...

http://s19.postimage.org/4171n7zhd/6465.gif


Did you divide by zero?
Link Posted: 12/27/2012 5:55:43 PM EDT
Originally Posted By TX_M1:
Originally Posted By notrega:
Explain this...

http://s19.postimage.org/4171n7zhd/6465.gif


Did you divide by zero?


did he eat Pi?
Link Posted: 12/27/2012 5:55:55 PM EDT
It's a white square, with a red X in it. Not too hard to explain.
Link Posted: 12/27/2012 5:56:26 PM EDT
Originally Posted By TX_M1:
Originally Posted By notrega:
Explain this...

http://s19.postimage.org/4171n7zhd/6465.gif


Did you divide by zero?


Link Posted: 12/27/2012 5:57:14 PM EDT
These "conundrums" usually involve violating some mundane and basic rule of arithmetic.

__________________________________________________________________
Cross-platform gun database/electronic bound book (v1.3.2) (and the original thread).
«nolite confidere in principibus, in filiis hominum quibus non est salus»
Link Posted: 12/27/2012 5:57:34 PM EDT
[Last Edit: 12/27/2012 5:57:57 PM EDT by notrega]
Originally Posted By MisterPX:
It's a white square, with a red X in it. Not too hard to explain.


I sees it...

ETA: Different Link

Link Posted: 12/27/2012 5:58:00 PM EDT
Dammit, here I was vegging on vacation and OP had to post this shit??

I watched the vid thing 50 damned times......I have no idea
Link Posted: 12/27/2012 5:58:25 PM EDT
Link Posted: 12/27/2012 5:58:35 PM EDT
But I learned 10 gross things that girls like to do in bed at that link

Link Posted: 12/27/2012 5:58:53 PM EDT
Originally Posted By 3Trip:
Originally Posted By TX_M1:
Originally Posted By notrega:
Explain this...

http://s19.postimage.org/4171n7zhd/6465.gif


Did you divide by zero?


did he eat Pi?


Everyone likes Pi right?
Link Posted: 12/27/2012 6:00:01 PM EDT
Originally Posted By PSYWAR1-0:
But I learned 10 gross things that girls like to do in bed at that link



I just subscribed to this discussion.
Link Posted: 12/27/2012 6:00:02 PM EDT
for those that can't see the gif

a square composed of 8x8 squareshas 64 squares

a rectangle with 5x13 is made out of that square by cutting it in to triangles and rearranging them

8x8 = 5x13
64=65
Link Posted: 12/27/2012 6:01:01 PM EDT
Sleight of graphics. When you run their graphics, you get 24.

All it takes is the slightest shift in the colored areas to gain 1 square. That is how it is done. If you do the geometry numerically, you get 64.

This is a version of sleight of hand, a magician's oldest trick.
Link Posted: 12/27/2012 6:01:06 PM EDT
bad math and poor resolution
Link Posted: 12/27/2012 6:01:15 PM EDT
I think the angles don't really line up, but I haven't got a way to stop the .gif and show it.

Obviously, it is not possible to do that.
Link Posted: 12/27/2012 6:01:34 PM EDT
You left gaps when reassembling it.
Link Posted: 12/27/2012 6:03:02 PM EDT
[Last Edit: 12/27/2012 6:03:31 PM EDT by mjrwood]
Not to be Captain Obvious, but 64 != 65. It's called faulty dissection and is achieved by loss of precision when splitting the units of the cubes.
Link Posted: 12/27/2012 6:03:30 PM EDT
The angles that the component polygons are cut at aren't the same.
There is 1 box volume of empty space in the middle of the right rectangle.
Link Posted: 12/27/2012 6:04:05 PM EDT
My best guess , it has something to do with the very small slivers of each triangle.
Link Posted: 12/27/2012 6:05:02 PM EDT
If you look at the animation, the squares don't match up. Simple as that. It's not 1:1.
Link Posted: 12/27/2012 6:05:28 PM EDT
Check out the angle of the diagonal line- the ratios of 3 to 8 and 2 to 5 aren't quite the same.
Link Posted: 12/27/2012 6:06:10 PM EDT
Originally Posted By Tolip:
The angles that the component polygons are cut at aren't the same.
There is 1 box volume of empty space in the middle of the right rectangle.


This is the correct answer.

The picture has been around awhile. The blue and red triangles actually have different slopes.
Link Posted: 12/27/2012 6:06:18 PM EDT
The angle for the 8x3 triangle is different than the 5x2 triangle that is a part of the two shapes at the bottom yet they line them up as if they magically fit together to get the extra unit.

It's all trickery.

Raffi
Link Posted: 12/27/2012 6:06:19 PM EDT



Link Posted: 12/27/2012 6:08:49 PM EDT


Really? Next you are going to try and tell me that Santa isn't real...
Link Posted: 12/27/2012 6:09:52 PM EDT
Link Posted: 12/27/2012 6:10:03 PM EDT
Originally Posted By notrega:


Really? Next you are going to try and tell me that Santa isn't real...


I've got bad news about the Tooth Fairy and the Easter Bunny, too.
Link Posted: 12/27/2012 6:10:04 PM EDT
Originally Posted By notrega:
Originally Posted By MisterPX:
It's a white square, with a red X in it. Not too hard to explain.


I sees it...

ETA: Different Link

http://gifs.gifbin.com/022010/1265701011_64-65.gif


Phew, for a moment, I thought 64=65 broke my laptop
Link Posted: 12/27/2012 6:10:34 PM EDT
Cucumber
Link Posted: 12/27/2012 6:10:58 PM EDT
Link Posted: 12/27/2012 6:11:51 PM EDT
Originally Posted By SparticleBrane:
Originally Posted By notrega:


Really? Next you are going to try and tell me that Santa isn't real...


I've got bad news about the Tooth Fairy and the Easter Bunny, too.


Don't tell me...
Link Posted: 12/27/2012 6:13:52 PM EDT
Originally Posted By ShoulderThing:
You left gaps when reassembling it.


Link Posted: 12/27/2012 6:14:32 PM EDT
A triangle can be reduced to an infinite number of triangles, each with a finite area.

If you add up an infinite number of finite areas you end up with infinite area. (infinity times any number equals infinity). WTFOMGBBQ?!!? Math is hard.

If I continuously close the distance between reality and my last statement by half, I would be walking forever.



Link Posted: 12/27/2012 6:15:34 PM EDT
Originally Posted By Keith_J:
Sleight of graphics. When you run their graphics, you get 24.

All it takes is the slightest shift in the colored areas to gain 1 square. That is how it is done. If you do the geometry numerically, you get 64.

This is a version of sleight of hand, a magician's oldest trick.


this, you can see it happening. Top right of the first image, when the red and green shift over. It does not shift all of the way to clear the other object. It is not possible to gain a sqaure unless you change the size of some or all of said squares. Just think of a pizza, not matter what angles you cut it at you will not get more pizza to appear.

It’s a stupid ‘trick’ if you ask me. People who don’t understand geometry (which is fine, I’m terrible at english/grammar’) are duped into thinking that it’s some complex epiphany. People who do understand geometry think it’s retarded, mainly because it violates basic logic. So it’s just preying on one half, and wasting the time of the other half. Not cleaver.
Link Posted: 12/27/2012 6:16:11 PM EDT
It is COLOR, not colour. Where in Canada are you?
Link Posted: 12/27/2012 6:23:40 PM EDT

Originally Posted By TheNarrator:
Originally Posted By Keith_J:
Sleight of graphics. When you run their graphics, you get 24.

All it takes is the slightest shift in the colored areas to gain 1 square. That is how it is done. If you do the geometry numerically, you get 64.

This is a version of sleight of hand, a magician's oldest trick.


this, you can see it happening. Top right of the first image, when the red and green shift over. It does not shift all of the way to clear the other object. It is not possible to gain a sqaure unless you change the size of some or all of said squares. Just think of a pizza, not matter what angles you cut it at you will not get more pizza to appear.

It’s a stupid ‘trick’ if you ask me. People who don’t understand geometry (which is fine, I’m terrible at english/grammar’) are duped into thinking that it’s some complex epiphany. People who do understand geometry think it’s retarded, mainly because it violates basic logic. So it’s just preying on one half, and wasting the time of the other half. Not cleaver.

The angles of the triangles must be identical. Rational math shows this to be false, 2/5 does not equal 3/8. In angle measurment in units of degrees, 2/5 is about 21.8 degrees. 3/8 is about 20.56 degrees. That is why you don't see the sleight of geometry.

I like how they used Chinese characters there .
Link Posted: 12/27/2012 6:28:01 PM EDT
Originally Posted By notrega:
Originally Posted By 3Trip:
Originally Posted By TX_M1:
Originally Posted By notrega:
Explain this...

http://s19.postimage.org/4171n7zhd/6465.gif


Did you divide by zero?


did he eat Pi?


Everyone likes Pi right?


Not StonerStudent?
Link Posted: 12/27/2012 6:32:43 PM EDT
Link Posted: 12/27/2012 6:35:04 PM EDT
And people think the chinese are going to surpass us in math.
Link Posted: 12/27/2012 6:38:14 PM EDT
[Last Edit: 12/27/2012 6:38:58 PM EDT by notrega]
How is this??

Dad: Playing a record? I'll show you something interesting. Compare a point on the label with a point on the record's outer edge. They both make a completed circle in the same amount of time, right?
Calvin: Yeah...
Dad: But the point on the record's edge has to make a bigger circle in the same time, so it goes faster. See, two points at two speeds even though they both make the same revolutions per minute!

Link Posted: 12/27/2012 6:40:50 PM EDT
Originally Posted By notrega:
Explain this...

http://s19.postimage.org/4171n7zhd/6465.gif


Having been in engineering graduate school with many Chinese students (actually, damn near all Chinese students) I can tell you the problem.

Chinese can't math.

Sure they might crank out some numbers, but the logic behind it? Lol, no.

Link Posted: 12/27/2012 6:43:45 PM EDT
Originally Posted By notrega:
How is this??

Dad: Playing a record? I'll show you something interesting. Compare a point on the label with a point on the record's outer edge. They both make a completed circle in the same amount of time, right?
Calvin: Yeah...
Dad: But the point on the record's edge has to make a bigger circle in the same time, so it goes faster. See, two points at two speeds even though they both make the same revolutions per minute!

http://s19.postimage.org/7algtonkz/id59968_xlarge.jpg


Love Calvin!!
Link Posted: 12/27/2012 6:49:14 PM EDT
[Last Edit: 12/27/2012 6:49:53 PM EDT by F22_RaptoR]
Originally Posted By notrega:
How is this??

Dad: Playing a record? I'll show you something interesting. Compare a point on the label with a point on the record's outer edge. They both make a completed circle in the same amount of time, right?
Calvin: Yeah...
Dad: But the point on the record's edge has to make a bigger circle in the same time, so it goes faster. See, two points at two speeds even though they both make the same revolutions per minute!

http://s19.postimage.org/7algtonkz/id59968_xlarge.jpg


Easy

As you get further away from the centre point of rotation, your speed has to increase to get the same revolutions per minute.

In reality if the 2 points were going the same velocity the outer edge would be going MUCH slower than the inside point, and would "torque" the record into oblivion.

It actually makes perfect sense, if you think about it for a bit.

PS, I love geometry, and Calivin and hobbs - so WIN
Link Posted: 12/27/2012 6:51:22 PM EDT
Originally Posted By Mosspointers:
Cucumber


static void MD5Transform(UINT4 state[4],
unsigned char block[64])

{

UINT4 a = state[0],
b = state[1],
c = state[2],
d = state[3],
x[16];

Decode (x, block, 64);

/* Round 1 */
FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */
FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */
FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */
FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */
FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */
FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */
FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */
FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */
FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */
FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */
FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */
FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */
FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */
FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */
FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */
FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */

/* Round 2 */
GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */
GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */
GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */
GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */
GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */
GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */
GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */
GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */
GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */
GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */
GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */
GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */
GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */
GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */
GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */
GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */

/* Round 3 */
HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */
HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */
HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */
HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */
HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */
HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */
HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */
HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */
HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */
HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */
HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */
HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */
HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */
HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */
HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */
HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */

/* Round 4 */
II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */
II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */
II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */
II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */
II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */
II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */
II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */
II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */
II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */
II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */
II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */
II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */
II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */
II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */
II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */
II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */

state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;

/* Zeroize sensitive information.*/
MD5_memset ((POINTER)x, 0, sizeof (x));
}
Link Posted: 12/27/2012 6:51:46 PM EDT
Magnets
Link Posted: 12/27/2012 6:54:22 PM EDT
[Last Edit: 12/27/2012 6:55:46 PM EDT by tc2k11]
Just for kicks...

The gap in the middle is not because I cut the lines crooked, it's because the angles of the designed cut make it so.


__________________________________________________________________
Cross-platform gun database/electronic bound book (v1.3.2) (and the original thread).
«nolite confidere in principibus, in filiis hominum quibus non est salus»
Link Posted: 12/27/2012 6:56:53 PM EDT
Originally Posted By ColonelPanic:
A triangle can be reduced to an infinite number of triangles, each with a finite area.

If you add up an infinite number of finite areas you end up with infinite area. (infinity times any number equals infinity). WTFOMGBBQ?!!? Math is hard.

If I continuously close the distance between reality and my last statement by half, I would be walking forever.







Link Posted: 12/27/2012 6:58:18 PM EDT
Originally Posted By tc2k11:
Just for kicks...

The gap in the middle is not because I cut the lines crooked, it's because the angles of the designed cut make it so.

http://i1102.photobucket.com/albums/g441/tc2k11arf/pics/64not65_zps40083ede.jpg
__________________________________________________________________
Cross-platform gun database/electronic bound book (v1.3.2) (and the original thread).
«nolite confidere in principibus, in filiis hominum quibus non est salus»


I was gonna do that, but I couldn't find a pad of graph paper.
Link Posted: 12/27/2012 7:02:17 PM EDT

Originally Posted By edb66:
Originally Posted By ColonelPanic:
A triangle can be reduced to an infinite number of triangles, each with a finite area.

If you add up an infinite number of finite areas you end up with infinite area. (infinity times any number equals infinity). WTFOMGBBQ?!!? Math is hard.

If I continuously close the distance between reality and my last statement by half, I would be walking forever.








"Of" denotes multiplication.
Link Posted: 12/27/2012 7:07:30 PM EDT
Originally Posted By MajorStumpDemon:
Originally Posted By Mosspointers:
Cucumber


static void MD5Transform(UINT4 state[4],
unsigned char block[64])

{

UINT4 a = state[0],
b = state[1],
c = state[2],
d = state[3],
x[16];

Decode (x, block, 64);

/* Round 1 */
FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */
FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */
FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */
FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */
FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */
FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */
FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */
FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */
FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */
FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */
FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */
FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */
FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */
FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */
FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */
FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */

/* Round 2 */
GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */
GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */
GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */
GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */
GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */
GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */
GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */
GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */
GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */
GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */
GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */
GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */
GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */
GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */
GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */
GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */

/* Round 3 */
HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */
HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */
HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */
HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */
HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */
HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */
HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */
HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */
HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */
HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */
HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */
HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */
HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */
HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */
HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */
HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */

/* Round 4 */
II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */
II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */
II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */
II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */
II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */
II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */
II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */
II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */
II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */
II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */
II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */
II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */
II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */
II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */
II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */
II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */

state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;

/* Zeroize sensitive information.*/
MD5_memset ((POINTER)x, 0, sizeof (x));
}



THIS
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