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did he eat Pi? |
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It's a white square, with a red X in it. Not too hard to explain.
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These "conundrums" usually involve violating some mundane and basic rule of arithmetic.
__________________________________________________________________ Cross-platform gun database/electronic bound book (v1.3.2) (and the original thread). «nolite confidere in principibus, in filiis hominum quibus non est salus» |
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Dammit, here I was vegging on vacation and OP had to post this shit??
I watched the vid thing 50 damned times......I have no idea |
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But I learned 10 gross things that girls like to do in bed at that link
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did he eat Pi? Everyone likes Pi right? |
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But I learned 10 gross things that girls like to do in bed at that link I just subscribed to this discussion. |
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for those that can't see the gif
a square composed of 8x8 squareshas 64 squares a rectangle with 5x13 is made out of that square by cutting it in to triangles and rearranging them 8x8 = 5x13 64=65 |
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Sleight of graphics. When you run their graphics, you get 24.
All it takes is the slightest shift in the colored areas to gain 1 square. That is how it is done. If you do the geometry numerically, you get 64. This is a version of sleight of hand, a magician's oldest trick. |
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I think the angles don't really line up, but I haven't got a way to stop the .gif and show it.
Obviously, it is not possible to do that. |
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Not to be Captain Obvious, but 64 != 65. It's called faulty dissection and is achieved by loss of precision when splitting the units of the cubes.
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The angles that the component polygons are cut at aren't the same.
There is 1 box volume of empty space in the middle of the right rectangle. |
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My best guess , it has something to do with the very small slivers of each triangle.
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If you look at the animation, the squares don't match up. Simple as that. It's not 1:1.
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Check out the angle of the diagonal line- the ratios of 3 to 8 and 2 to 5 aren't quite the same.
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The angles that the component polygons are cut at aren't the same. There is 1 box volume of empty space in the middle of the right rectangle. This is the correct answer. The picture has been around awhile. The blue and red triangles actually have different slopes. |
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The angle for the 8x3 triangle is different than the 5x2 triangle that is a part of the two shapes at the bottom yet they line them up as if they magically fit together to get the extra unit.
It's all trickery. Raffi |
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http://www.cultura.ufpa.br/dicas/fig/64-65b.jpg http://www.profkrishna.com/ProfK-Images/64-65Puzzle.jpg Really? Next you are going to try and tell me that Santa isn't real... |
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http://www.cultura.ufpa.br/dicas/fig/64-65b.jpg http://www.profkrishna.com/ProfK-Images/64-65Puzzle.jpg Really? Next you are going to try and tell me that Santa isn't real... I've got bad news about the Tooth Fairy and the Easter Bunny, too. |
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It's a white square, with a red X in it. Not too hard to explain. I sees it... ETA: Different Link http://gifs.gifbin.com/022010/1265701011_64-65.gif Phew, for a moment, I thought 64=65 broke my laptop |
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http://www.cultura.ufpa.br/dicas/fig/64-65b.jpg http://www.profkrishna.com/ProfK-Images/64-65Puzzle.jpg Really? Next you are going to try and tell me that Santa isn't real... I've got bad news about the Tooth Fairy and the Easter Bunny, too. Don't tell me... |
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A triangle can be reduced to an infinite number of triangles, each with a finite area.
If you add up an infinite number of finite areas you end up with infinite area. (infinity times any number equals infinity). WTFOMGBBQ?!!? Math is hard. If I continuously close the distance between reality and my last statement by half, I would be walking forever. |
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Sleight of graphics. When you run their graphics, you get 24. All it takes is the slightest shift in the colored areas to gain 1 square. That is how it is done. If you do the geometry numerically, you get 64. This is a version of sleight of hand, a magician's oldest trick. this, you can see it happening. Top right of the first image, when the red and green shift over. It does not shift all of the way to clear the other object. It is not possible to gain a sqaure unless you change the size of some or all of said squares. Just think of a pizza, not matter what angles you cut it at you will not get more pizza to appear. It’s a stupid ‘trick’ if you ask me. People who don’t understand geometry (which is fine, I’m terrible at english/grammar’) are duped into thinking that it’s some complex epiphany. People who do understand geometry think it’s retarded, mainly because it violates basic logic. So it’s just preying on one half, and wasting the time of the other half. Not cleaver. |
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Quoted: Quoted: Sleight of graphics. When you run their graphics, you get 24. All it takes is the slightest shift in the colored areas to gain 1 square. That is how it is done. If you do the geometry numerically, you get 64. This is a version of sleight of hand, a magician's oldest trick. this, you can see it happening. Top right of the first image, when the red and green shift over. It does not shift all of the way to clear the other object. It is not possible to gain a sqaure unless you change the size of some or all of said squares. Just think of a pizza, not matter what angles you cut it at you will not get more pizza to appear. It’s a stupid ‘trick’ if you ask me. People who don’t understand geometry (which is fine, I’m terrible at english/grammar’) are duped into thinking that it’s some complex epiphany. People who do understand geometry think it’s retarded, mainly because it violates basic logic. So it’s just preying on one half, and wasting the time of the other half. Not cleaver. The angles of the triangles must be identical. Rational math shows this to be false, 2/5 does not equal 3/8. In angle measurment in units of degrees, 2/5 is about 21.8 degrees. 3/8 is about 20.56 degrees. That is why you don't see the sleight of geometry. I like how they used Chinese characters there . |
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did he eat Pi? Everyone likes Pi right? Not StonerStudent? |
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And people think the chinese are going to surpass us in math.
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Having been in engineering graduate school with many Chinese students (actually, damn near all Chinese students) I can tell you the problem. Chinese can't math. Sure they might crank out some numbers, but the logic behind it? Lol, no. |
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How is this?? Dad: Playing a record? I'll show you something interesting. Compare a point on the label with a point on the record's outer edge. They both make a completed circle in the same amount of time, right? Calvin: Yeah... Dad: But the point on the record's edge has to make a bigger circle in the same time, so it goes faster. See, two points at two speeds even though they both make the same revolutions per minute! http://s19.postimage.org/7algtonkz/id59968_xlarge.jpg Love Calvin!! |
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How is this?? Dad: Playing a record? I'll show you something interesting. Compare a point on the label with a point on the record's outer edge. They both make a completed circle in the same amount of time, right? Calvin: Yeah... Dad: But the point on the record's edge has to make a bigger circle in the same time, so it goes faster. See, two points at two speeds even though they both make the same revolutions per minute! http://s19.postimage.org/7algtonkz/id59968_xlarge.jpg Easy As you get further away from the centre point of rotation, your speed has to increase to get the same revolutions per minute. In reality if the 2 points were going the same velocity the outer edge would be going MUCH slower than the inside point, and would "torque" the record into oblivion. It actually makes perfect sense, if you think about it for a bit. PS, I love geometry, and Calivin and hobbs - so WIN |
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Cucumber static void MD5Transform(UINT4 state[4], unsigned char block[64]) { UINT4 a = state[0], b = state[1], c = state[2], d = state[3], x[16]; Decode (x, block, 64); /* Round 1 */ FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */ FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */ FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */ FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */ FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */ FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */ FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */ FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */ FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */ FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */ FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */ FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */ FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */ FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */ FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */ FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */ /* Round 2 */ GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */ GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */ GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */ GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */ GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */ GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */ GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */ GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */ GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */ GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */ GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */ GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */ GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */ GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */ GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */ GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */ /* Round 3 */ HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */ HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */ HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */ HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */ HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */ HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */ HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */ HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */ HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */ HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */ HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */ HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */ HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */ HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */ HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */ HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */ /* Round 4 */ II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */ II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */ II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */ II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */ II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */ II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */ II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */ II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */ II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */ II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */ II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */ II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */ II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */ II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */ II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */ II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */ state[0] += a; state[1] += b; state[2] += c; state[3] += d; /* Zeroize sensitive information.*/ MD5_memset ((POINTER)x, 0, sizeof (x)); } |
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Just for kicks...
The gap in the middle is not because I cut the lines crooked, it's because the angles of the designed cut make it so. __________________________________________________________________ Cross-platform gun database/electronic bound book (v1.3.2) (and the original thread). «nolite confidere in principibus, in filiis hominum quibus non est salus» |
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A triangle can be reduced to an infinite number of triangles, each with a finite area. If you add up an infinite number of finite areas you end up with infinite area. (infinity times any number equals infinity). WTFOMGBBQ?!!? Math is hard. If I continuously close the distance between reality and my last statement by half, I would be walking forever. |
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Just for kicks... The gap in the middle is not because I cut the lines crooked, it's because the angles of the designed cut make it so. http://i1102.photobucket.com/albums/g441/tc2k11arf/pics/64not65_zps40083ede.jpg __________________________________________________________________ Cross-platform gun database/electronic bound book (v1.3.2) (and the original thread). «nolite confidere in principibus, in filiis hominum quibus non est salus» I was gonna do that, but I couldn't find a pad of graph paper. |
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Quoted: Quoted: A triangle can be reduced to an infinite number of triangles, each with a finite area. If you add up an infinite number of finite areas you end up with infinite area. (infinity times any number equals infinity). WTFOMGBBQ?!!? Math is hard. If I continuously close the distance between reality and my last statement by half, I would be walking forever. "Of" denotes multiplication. |
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Cucumber static void MD5Transform(UINT4 state[4], unsigned char block[64]) { UINT4 a = state[0], b = state[1], c = state[2], d = state[3], x[16]; Decode (x, block, 64); /* Round 1 */ FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */ FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */ FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */ FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */ FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */ FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */ FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */ FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */ FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */ FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */ FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */ FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */ FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */ FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */ FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */ FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */ /* Round 2 */ GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */ GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */ GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */ GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */ GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */ GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */ GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */ GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */ GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */ GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */ GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */ GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */ GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */ GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */ GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */ GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */ /* Round 3 */ HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */ HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */ HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */ HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */ HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */ HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */ HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */ HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */ HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */ HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */ HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */ HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */ HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */ HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */ HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */ HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */ /* Round 4 */ II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */ II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */ II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */ II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */ II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */ II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */ II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */ II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */ II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */ II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */ II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */ II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */ II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */ II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */ II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */ II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */ state[0] += a; state[1] += b; state[2] += c; state[3] += d; /* Zeroize sensitive information.*/ MD5_memset ((POINTER)x, 0, sizeof (x)); } THIS I Think |
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