Quoted:
Quoted:
Quoted: Dist = ((XCoord2-XCoord1)^2+(YCoord2-YCoord1)^2)^(1/2)
Or, the distance is the square root of the sum of the squares of the differences of the coordinates. Pythagorean theorem and all that.
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As long as it's on a grid. If the coordinates are geodetic (lat long) it gets messed up because the further from the equator, the bigger the difference between the X and Y axis (in terms of how far, in feet or miles or whatever, one degree is).
| I'm presuming that the poster has a coordinate system on a rectangular plane. If he's got a more sophisticated coordinate system, then he will need mapping software to account for the datum projections.
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I sorta figure the poster doesn't even know what a coordinate system is - most people don't - so he PROBABLY has lat/long coordinates.
Chances are, if he had coordinates in one of the various state planes, he waouldn't be asking for our help anyway.
Either way, it amazes me how many arfcommers understand his problem well enough to help him.
We should form a corporation.
'Hive Mind All-Purpose Tech Support'.