[ARCHIVED THREAD] - Partial derivatives Help!

Posted: 6/2/2006 9:35:32 AM EDT

f(x,y) = 8x^2 + 8y^2 - 8x^2y + 6

can you help me with?

fx(x,y)

and

fy(x,y)

Posted: 6/2/2006 9:44:10 AM EDT

[#1]

Posted: 6/2/2006 9:46:18 AM EDT

[#2]

?? Free bump..

Posted: 6/2/2006 9:46:48 AM EDT

[#3]

Do you mean:
f(x,y) = 8x^2 + 8y^2 - (8x^2)y + 6

Is so, then these are the answers:

fx(x,y) = 16x-16xy

fy(x,y)= 16y-8x^2

Posted: 6/2/2006 9:48:34 AM EDT

[#4]

partial derivatives:

fx(x,y) = 16x - 16xy

fy(x,y) = 16y - 8x^2

if i understood your format right. I'd post an explanation but i'm really short on time.

Posted: 6/2/2006 9:50:15 AM EDT

[#5]

just take two individual derivatives, one with respect to x, the other with respect to y.

For the derivative with respect to x, treat y as a constant and x as a variable.

For the derivative with respect to y, treat x as a constant and y as a variable

Posted: 6/2/2006 9:51:07 AM EDT

[#6]

JL7,
Do you need an explanation, or can you understand from my response?

Good luck!
AE

Posted: 6/2/2006 9:52:01 AM EDT

[#7]

Posted: 6/2/2006 9:52:09 AM EDT

[#8]

When differentiation partially for x, treat the y as constant.

Same for when differentiating for y, hold x.

Pretty simple, all in all.

Fx(x,y)=16x-16xy
Fy(x,y)=16y-8x^2

[ARCHIVED THREAD] - Partial derivatives Help!

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[ARCHIVED THREAD] - Partial derivatives Help!

[ARCHIVED THREAD] - Partial derivatives Help!