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AR15.COM
3/8/2003 2:35:08 PM EDT
The definite integral of (sin(2x) * cos(x) dx) bounds: lower limit 0 upper limit 1
I've gotten as far as to conclude that you must use u substitution. I know the integral of sin(2x) = 1/2 -cos 2x + C and the integral of cos x = sin x + C but since you cant just multiply the two together and use the fundamental theorem i am lost. Heeeelp please. I have tried like 100 quadrillion times alright and I am doing something wrong.
3/8/2003 2:37:12 PM EDT
[#1]
The answer is either Jesus or the wind.
The answer is ALWAYS either Jesus or the wind.
3/8/2003 2:43:16 PM EDT
[#2]
Notice that Sin(2x) = 2sin(x)cos(x).

I'm taking applied math in the University of Waterloo.
3/8/2003 2:46:18 PM EDT
[#3]
The XDR-34 nucomplector of your problem is skewed. You need an XDR-35 component and a flux capacitor wired in a parallel configuration to make it work.

Glad I could finally help someone on the site.
3/8/2003 2:48:16 PM EDT
[#4]
I believe what you have to do for this one is use integration by parts twice. After you do it the second time, the integral should be the same as the original integral. You then write the equation with the original integral equals the results of the two integrations by parts. You can then add the integral that integration by parts gave you on one side to the original integral on the other side, and the resulting equation will be the original integral equals some function of x, and that is the solution.
3/8/2003 2:48:50 PM EDT
[#5]
That's funny. The last word I understood of the original post was the first [i]"The"[/i].