Posted: 8/9/2014 9:04:47 AM EDT
| I just bought 2 sticks of 2gb ddr2 pc2 4200 533mhz ram. My computer says that only 3.25 gigs are useable. Are there any reasons why this is? |
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http://windows.microsoft.com/en-us/windows7/find-out-32-or-64-bit
Tell us what it says. |
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Quoted:
Not true 32 bit operating systems can see 8 gigs, 64 bit operating systems can see 16 gigs. Quoted:
Quoted:
The system reserves some ram no matter how much ram is installed. 32 bit cannot address more than 4g (3.5g) of ram. Not true 32 bit operating systems can see 8 gigs, 64 bit operating systems can see 16 gigs. Uhm.... No. 32-Bit = 4 gigs
A 32-bit register can store 232 different values. The signed range of integer values that can be stored in 32 bits is -2,147,483,648 through 2,147,483,647 (unsigned: 0 through 4,294,967,295). Hence, a processor with 32-bit memory addresses can directly access 4 GiB of byte-addressable memory. 64-Bit = 16 exbibytes
A 64-bit register can store 264 (over 18 quintillion or 1.8×1019) different values. Hence, a processor with 64-bit memory addresses can directly access 264 bytes (=16 exbibytes) of byte-addressable memory. |
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Quoted:
Uhm.... No. Quoted:
Quoted:
Quoted:
The system reserves some ram no matter how much ram is installed. 32 bit cannot address more than 4g (3.5g) of ram. Not true 32 bit operating systems can see 8 gigs, 64 bit operating systems can see 16 gigs. Uhm.... No. 32-Bit = 4 gigs
A 32-bit register can store 232 different values. The signed range of integer values that can be stored in 32 bits is -2,147,483,648 through 2,147,483,647 (unsigned: 0 through 4,294,967,295). Hence, a processor with 32-bit memory addresses can directly access 4 GiB of byte-addressable memory. 64-Bit = 16 exbibytes
A 64-bit register can store 264 (over 18 quintillion or 1.8×1019) different values. Hence, a processor with 64-bit memory addresses can directly access 264 bytes (=16 exbibytes) of byte-addressable memory. I said "can see" and didn't say "can use". But your point is made and I agree. |