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AR15.COM
1/30/2012 5:49:17 PM EDT
So, I'm trying to help my girlfriend with her online statistics class.  I have an engineering degree, so it should be easy peasy right?  Well it mostly is, but this homework problem has me all .  I'm sure I'm missing something easy, and I'm just not spotting it.

The problem is to create a grouped frequency distribution chart for a list of numbers with 7 classes.

The numbers are:

88 88 110 88 80 69 102 78 70 55 79 85 80 100 60 90 77 55 75 55 54 60 75 64 105 56 71 70 65 72

Highest number: 110

Lowest number: 54

Range = highest -lowest = 110 - 54 = 56

Width = (range/number of classes) = 56/7 = 8

So starting with the lowest number and added the class width, I get these classes:

54 -> 61
62 -> 69
70 -> 77
78 -> 85
86 -> 93
94 -> 101
102 -> 109

That doesn't work since the highest number (110) doesn't fall into the limits of the highest class.  

When I change the class width to 9 it works, but that doesn't follow the textbook's method.  It's just my way of fudging it to make the chart work.

Am I missing something simple here?

Thanks.

1/30/2012 5:55:55 PM EDT
[#1]
Rules is rules.
1/30/2012 5:56:37 PM EDT
[#2]
Nice jeans!
1/30/2012 5:57:16 PM EDT
[#3]
Dat gap!
1/30/2012 5:57:31 PM EDT
[#4]
Quoted:
Nice jeans!


1/30/2012 5:57:46 PM EDT
[#5]
1/30/2012 5:58:32 PM EDT
[#6]
What do you think we are, Sherlock?
1/30/2012 5:58:42 PM EDT
[#7]
With that pic of your girlfriend I think your best answer is 69 everytime.
1/30/2012 5:58:50 PM EDT
[#8]


Haven't you already posted that pic a couple of times???
1/30/2012 5:59:48 PM EDT
[#9]
87?
1/30/2012 6:00:23 PM EDT
[#10]
Quoted:


Haven't you already posted that pic a couple of times???


Yes.  It satisfies the requirement but doesn't show her face
1/30/2012 6:00:32 PM EDT
[#11]
Well, I recommend her ass to be the answer.
1/30/2012 6:00:37 PM EDT
[#12]
Quoted:
So, I'm trying to help my girlfriend with her online statistics class.  I have an engineering degree, so it should be easy peasy right?  Well it mostly is, but this homework problem has me all .  I'm sure I'm missing something easy, and I'm just not spotting it.

The problem is to create a grouped frequency distribution chart for a list of numbers with 7 classes.

The numbers are:

88 88 110 88 80 69 102 78 70 55 79 85 80 100 60 90 77 55 75 55 54 60 75 64 105 56 71 70 65 72

Highest number: 110

Lowest number: 54

Range = highest -lowest = 110 - 54 = 56 N +1

Width = (range/number of classes) = 56/7 = 8

So starting with the lowest number and added the class width, I get these classes:

54 -> 61
62 -> 69
70 -> 77
78 -> 85
86 -> 93
94 -> 101
102 -> 109

That doesn't work since the highest number (110) doesn't fall into the limits of the highest class.  

When I change the class width to 9 it works, but that doesn't follow the textbook's method.  It's just my way of fudging it to make the chart work.

Am I missing something simple here?

Thanks.



1/30/2012 6:01:06 PM EDT
[#13]
User Name + Pic = related
1/30/2012 6:01:11 PM EDT
[#14]
Can you change the size of the groups?  Does standard deviation have any bearing on your sample?
1/30/2012 6:02:08 PM EDT
[#15]
That could be you for all we know.

Fkn A man. Dont be a tease. Show the front.
1/30/2012 6:04:25 PM EDT
[#16]
Quoted:
Quoted:
So, I'm trying to help my girlfriend with her online statistics class.  I have an engineering degree, so it should be easy peasy right?  Well it mostly is, but this homework problem has me all .  I'm sure I'm missing something easy, and I'm just not spotting it.

The problem is to create a grouped frequency distribution chart for a list of numbers with 7 classes.

The numbers are:

88 88 110 88 80 69 102 78 70 55 79 85 80 100 60 90 77 55 75 55 54 60 75 64 105 56 71 70 65 72

Highest number: 110

Lowest number: 54

Range = highest -lowest = 110 - 54 = 56 N +1

Width = (range/number of classes) = 56/7 = 8

So starting with the lowest number and added the class width, I get these classes:

54 -> 61
62 -> 69
70 -> 77
78 -> 85
86 -> 93
94 -> 101
102 -> 109

That doesn't work since the highest number (110) doesn't fall into the limits of the highest class.  

When I change the class width to 9 it works, but that doesn't follow the textbook's method.  It's just my way of fudging it to make the chart work.

Am I missing something simple here?

Thanks.



He got it. It is always N+1 when determining Range.

1/30/2012 6:04:35 PM EDT
[#17]
She has an ass like Couch-Commando.
1/30/2012 6:04:49 PM EDT
[#18]
I'm not as polite as Dan.



DAT ASS!


Hit it hard.
1/30/2012 6:05:58 PM EDT
[#19]
Quoted:
Quoted:
So, I'm trying to help my girlfriend with her online statistics class.  I have an engineering degree, so it should be easy peasy right?  Well it mostly is, but this homework problem has me all .  I'm sure I'm missing something easy, and I'm just not spotting it.

The problem is to create a grouped frequency distribution chart for a list of numbers with 7 classes.

The numbers are:

88 88 110 88 80 69 102 78 70 55 79 85 80 100 60 90 77 55 75 55 54 60 75 64 105 56 71 70 65 72

Highest number: 110

Lowest number: 54

Range = highest -lowest = 110 - 54 = 56 N +1

Width = (range/number of classes) = 56/7 = 8

So starting with the lowest number and added the class width, I get these classes:

54 -> 61
62 -> 69
70 -> 77
78 -> 85
86 -> 93
94 -> 101
102 -> 109

That doesn't work since the highest number (110) doesn't fall into the limits of the highest class.  

When I change the class width to 9 it works, but that doesn't follow the textbook's method.  It's just my way of fudging it to make the chart work.

Am I missing something simple here?

Thanks.





That makes sense because there are 57 numbers from 54-110 (including 54).  So work it with class width of 9 since that's the next integer after the decimal range value?

Damn textbook mentions nothing about N+1, and of course the examples workout just fine without it.  Thanks guys!
1/30/2012 6:07:36 PM EDT
[#20]
Quoted:
Well, I recommend her ass to be the answer.


1/30/2012 6:07:37 PM EDT
[#21]


Nice Caboose
1/30/2012 6:08:14 PM EDT
[#22]
I've got nothing. But jeans are the
1/30/2012 6:08:37 PM EDT
[#23]
1/30/2012 6:09:07 PM EDT
[#24]
Quoted:
That could be you for all we know.

Fkn A man. Dont be a tease. Show the front.


Yup, that's my hairy man ass....
1/30/2012 6:09:15 PM EDT
[#25]
needs more pics
1/30/2012 6:09:39 PM EDT
[#26]


1/30/2012 6:10:31 PM EDT
[#27]




Quoted:

So, I'm trying to help my girlfriend with her online statistics class. I have an engineering degree, so it should be easy peasy right? Well it mostly is, but this homework problem has me all . I'm sure I'm missing something easy, and I'm just not spotting it.



The problem is to create a grouped frequency distribution chart for a list of numbers with 7 classes.



The numbers are:



88 88 110 88 80 69 102 78 70 55 79 85 80 100 60 90 77 55 75 55 54 60 75 64 105 56 71 70 65 72



Highest number: 110



Lowest number: 54



Range = highest -lowest = 110 - 54 = 56



Width = (range/number of classes) = 56/7 = 8



So starting with the lowest number and added the class width, I get these classes:



54 -> 61

62 -> 69

70 -> 77

78 -> 85

86 -> 93

94 -> 101

102 -> 109



That doesn't work since the highest number (110) doesn't fall into the limits of the highest class.



When I change the class width to 9 it works, but that doesn't follow the textbook's method. It's just my way of fudging it to make the chart work.



Am I missing something simple here?



Thanks.







Am I missing something here?  Your class widths are 7, not 8.  Shouldn't they be:



54 <= X <= 62

62 < X <= 70

70 < X <= 78

78 < X <= 86

86 < X <= 94

94 < X <= 102

102 < X <= 110
1/30/2012 6:11:20 PM EDT
[#28]





Quoted:





Quoted:




Quoted:


So, I'm trying to help my girlfriend with her online statistics class.  I have an engineering degree, so it should be easy peasy right?  Well it mostly is, but this homework problem has me all .  I'm sure I'm missing something easy, and I'm just not spotting it.





The problem is to create a grouped frequency distribution chart for a list of numbers with 7 classes.





The numbers are:





88 88 110 88 80 69 102 78 70 55 79 85 80 100 60 90 77 55 75 55 54 60 75 64 105 56 71 70 65 72





Highest number: 110





Lowest number: 54





Range = highest -lowest = 110 - 54 = 56 N +1





Width = (range/number of classes) = 56/7 = 8





So starting with the lowest number and added the class width, I get these classes:





54 -> 61


62 -> 69


70 -> 77


78 -> 85


86 -> 93


94 -> 101


102 -> 109





That doesn't work since the highest number (110) doesn't fall into the limits of the highest class.  





When I change the class width to 9 it works, but that doesn't follow the textbook's method.  It's just my way of fudging it to make the chart work.





Am I missing something simple here?





Thanks.











He got it. It is always N+1 when determining Range.










Bingo! Funny, I was just helping my wife with a statistics class since she just started on her masters. I'm also an engineer.



ETA: I'm fairly certain that my wife's text book indicated that the range is N + 1.
 
1/30/2012 6:12:32 PM EDT
[#29]
Quoted:
Quoted:
Quoted:
So, I'm trying to help my girlfriend with her online statistics class.  I have an engineering degree, so it should be easy peasy right?  Well it mostly is, but this homework problem has me all .  I'm sure I'm missing something easy, and I'm just not spotting it.

The problem is to create a grouped frequency distribution chart for a list of numbers with 7 classes.

The numbers are:

88 88 110 88 80 69 102 78 70 55 79 85 80 100 60 90 77 55 75 55 54 60 75 64 105 56 71 70 65 72

Highest number: 110

Lowest number: 54

Range = highest -lowest = 110 - 54 = 56 N +1

Width = (range/number of classes) = 56/7 = 8

So starting with the lowest number and added the class width, I get these classes:

54 -> 61
62 -> 69
70 -> 77
78 -> 85
86 -> 93
94 -> 101
102 -> 109

That doesn't work since the highest number (110) doesn't fall into the limits of the highest class.  

When I change the class width to 9 it works, but that doesn't follow the textbook's method.  It's just my way of fudging it to make the chart work.

Am I missing something simple here?

Thanks.





That makes sense because there are 57 numbers from 54-110 (including 54).  So work it with class width of 9 since that's the next integer after the decimal range value?

Damn textbook mentions nothing about N+1, and of course the examples workout just fine without it.  Thanks guys!


You can do it that way, though you will introduce a certain degree of skew into your data that way since your highest class will be 108 -> 116. You can use decimal widths if that's allowed (i.e. width 8.14) or you can pad the highest class to be 102 -> 110; according to my notes from Engineering Prob&Stats, classes are ALMOST always equal in length but do not necessarily have to be.
1/30/2012 6:14:07 PM EDT
[#30]
Quoted:

Quoted:
So, I'm trying to help my girlfriend with her online statistics class. I have an engineering degree, so it should be easy peasy right? Well it mostly is, but this homework problem has me all . I'm sure I'm missing something easy, and I'm just not spotting it.

The problem is to create a grouped frequency distribution chart for a list of numbers with 7 classes.

The numbers are:

88 88 110 88 80 69 102 78 70 55 79 85 80 100 60 90 77 55 75 55 54 60 75 64 105 56 71 70 65 72

Highest number: 110

Lowest number: 54

Range = highest -lowest = 110 - 54 = 56

Width = (range/number of classes) = 56/7 = 8

So starting with the lowest number and added the class width, I get these classes:

54 -> 61
62 -> 69
70 -> 77
78 -> 85
86 -> 93
94 -> 101
102 -> 109

That doesn't work since the highest number (110) doesn't fall into the limits of the highest class.

When I change the class width to 9 it works, but that doesn't follow the textbook's method. It's just my way of fudging it to make the chart work.

Am I missing something simple here?

Thanks.



Am I missing something here?  Your class widths are 7, not 8.  Shouldn't they be:

54 <= X <= 62
62 < X <= 70
70 < X <= 78
78 < X <= 86
86 < X <= 94
94 < X <= 102
102 < X <= 110


No, it's left end inclusive. Counting the numbers from 54 to 61 gives eight numbers - 54, 55, 56, 57, 58, 59, 60, 61.
1/30/2012 6:15:13 PM EDT
[#31]
Quoted:
Quoted:
So, I'm trying to help my girlfriend with her online statistics class.  I have an engineering degree, so it should be easy peasy right?  Well it mostly is, but this homework problem has me all .  I'm sure I'm missing something easy, and I'm just not spotting it.

The problem is to create a grouped frequency distribution chart for a list of numbers with 7 classes.

The numbers are:

88 88 110 88 80 69 102 78 70 55 79 85 80 100 60 90 77 55 75 55 54 60 75 64 105 56 71 70 65 72

Highest number: 110

Lowest number: 54

Range = highest -lowest = 110 - 54 = 56 N +1

Width = (range/number of classes) = 56/7 = 8

So starting with the lowest number and added the class width, I get these classes:

54 -> 61
62 -> 69
70 -> 77
78 -> 85
86 -> 93
94 -> 101
102 -> 109

That doesn't work since the highest number (110) doesn't fall into the limits of the highest class.  

When I change the class width to 9 it works, but that doesn't follow the textbook's method.  It's just my way of fudging it to make the chart work.

Am I missing something simple here?

Thanks.





I think he's got it. If you have two data items, 1 and 2, you need to add +1 to the higher value or else you will not include both of the values. 2-1=1. 3-1=2. You have two values, not one.