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Sponsor News TNVC: NEW and Exclusive Filmed SuperGain (FSG) Image Intensifier Tubes & Chimera Pano Giveaway!!
9/20/2005 2:10:37 PM EDT
Two planes each drop a bomb. At the moment of release each plane has the same speed of 131 m/s, and each bomb is at the same height of 2.00 km above the ground. Although the speeds are the same, the velocities are different at the instant of release, because one plane is flying at an angle of 15.0° above the horizontal and the other is flying at an angle of 15.0° below the horizontal.

What is the velocity and angle at which the bombs land on the insurgents below?
9/20/2005 2:11:48 PM EDT
[#1]
Guess I don't care as long as they hit the intended target...
9/20/2005 2:13:30 PM EDT
[#2]
what's the wind speed and direction?    
9/20/2005 2:15:00 PM EDT
[#3]
We disregard wind resistance?
9/20/2005 2:15:34 PM EDT
[#4]
Nah, you need to give us all sorts of additional info, such as mass, coefficient of drag and ballistic coefficient of the bomb versus velocity.  Are the two bombs identical bombs?
9/20/2005 2:17:06 PM EDT
[#5]
The answer is 3
9/20/2005 2:18:41 PM EDT
[#6]
Quoted:
The answer is 3
www.tootsie.com/img/thumbnailMrowl.gif
9/20/2005 2:19:26 PM EDT
[#7]
Is that an African or European swallow?

Terminal velocity, headed straight down for both bombs. That's my guess.
9/20/2005 2:21:58 PM EDT
[#8]
Quoted:
We disregard wind resistance?


keep it simple, disregard wind resistance.

The bombs are identical, you don't need mass.  AsubG = acceleration due to gravity = -9.8 m/s^2
9/20/2005 2:26:44 PM EDT
[#9]
Quoted:

What is the velocity and angle at which the bombs land on the insurgents below?


Do you mean to ask for speed and angle or velocity (a vector quantity)?


Omit air resistance?????  
9/20/2005 2:30:02 PM EDT
[#10]
Quoted:
Quoted:

What is the velocity and angle at which the bombs land on the insurgents below?


Do you mean to ask for speed and angle or velocity (a vector quantity)?


Omit air resistance?????  
 Sorry, it asks for SPEED and ANGLE.  sorry.
9/20/2005 2:30:45 PM EDT
[#11]
Quoted:
Quoted:
Quoted:

What is the velocity and angle at which the bombs land on the insurgents below?


Do you mean to ask for speed and angle or velocity (a vector quantity)?


Omit air resistance?????  
 Sorry, it asks for SPEED and ANGLE.  sorry.




So, basically, you want us to do your homework for you, is that it?
9/20/2005 2:33:59 PM EDT
[#12]
Quoted:
Quoted:
Quoted:
Quoted:

What is the velocity and angle at which the bombs land on the insurgents below?


Do you mean to ask for speed and angle or velocity (a vector quantity)?


Omit air resistance?????  
 Sorry, it asks for SPEED and ANGLE.  sorry.




So, basically, you want us to do your homework for you, is that it?




I think so.
9/20/2005 2:34:35 PM EDT
[#13]
I think I need ballistic coefficient or a brain or something.

Regards,
Mild Bill
9/20/2005 2:36:12 PM EDT
[#14]
Quoted:
Quoted:
We disregard wind resistance?


keep it simple, disregard wind resistance.

The bombs are identical, you don't need mass.  AsubG = acceleration due to gravity = -9.8 m/s^2


Omit terminal velocity?
9/20/2005 2:36:46 PM EDT
[#15]
Do your homework yourself. You won't learn anything if you ask ARFCOM to do it for you. You probably won't even get it right that way either.
9/20/2005 2:37:34 PM EDT
[#16]
does one bomb land at 324.69 m/s and the other at 329.16 m/s?  not sure about the angles though.
9/20/2005 2:38:38 PM EDT
[#17]
First bomb lands at an angle of 13 degrees 23 minutes 12 seconds at a velocity of 134 meters/sec

Second bomb will land at 16 degrees 32 minutes 15 seconds with the same velocity. Assuming both are painted olive drab and the planes have proper tire inflation.

We were doing this stuff in the third grade...
9/20/2005 2:48:20 PM EDT
[#18]
Quoted:
Quoted:
Quoted:
Quoted:
Quoted:

What is the velocity and angle at which the bombs land on the insurgents below?


Do you mean to ask for speed and angle or velocity (a vector quantity)?


Omit air resistance?????  
 Sorry, it asks for SPEED and ANGLE.  sorry.




So, basically, you want us to do your homework for you, is that it?




I think so.




I have already got the correct answer to this problem, thank you very much...

No one has the correct answer yet.
terminal velocity is not used in this problem.
9/20/2005 2:53:31 PM EDT
[#19]
Irrelevant question.  Because one plane was flying at 15 degrees above horizontal and the other 15 degrees below, the planes crashed into each other and the bombs explode on impact.
9/20/2005 2:55:33 PM EDT
[#20]
Quoted:
Irrelevant question.  Because one plane was flying at 15 degrees above horizontal and the other 15 degrees below, the planes crashed into each other and the bombs explode on impact.


Very Good!!!!


No, here is a hint, the bombs will have the same speed and angle....and they will do a lot of damage.
9/20/2005 3:13:17 PM EDT
[#21]
scratched it out real quick so i donno if its correct yet, havent had time to check. about 237 m/s @ about 58 degrees, and the other about 232 at 57 degrees.
9/20/2005 3:13:37 PM EDT
[#22]
Quoted:
Quoted:
Quoted:
We disregard wind resistance?


keep it simple, disregard wind resistance.

The bombs are identical, you don't need mass.  AsubG = acceleration due to gravity = -9.8 m/s^2


Omit terminal velocity?


If you disregard wind resistance, then velocity will continue to increase until impact
9/20/2005 3:16:11 PM EDT
[#23]
What do you mean the speeds are the same but the velocities are different?
9/20/2005 3:17:27 PM EDT
[#24]
Quoted:
What do you mean the speeds are the same but the velocities are different?


A velocity is a vector quantity, magnitude and direction. Both bombs will have to have the same magnitude of forward motion or "speed". Speed is a directionless quantity.
9/20/2005 3:29:44 PM EDT
[#25]
yea but what i want to know is did the bombs hit the target!
9/20/2005 3:41:26 PM EDT
[#26]
v = dx/dy A (Acceleration is the level that gravity and friction act upon as a multiplier)

A having a vertical and horizontal component, being acted upon by gravity at around 9.8m/s2 for each projectile being released at +/- 15 degree increments. One will arc, the other will dive.

Its a fundamental time & distance equation, for which I have drunk too much wine at this time to contemplate.


Forward velocity will be equal in the absence of friction, being the forward derivative of acceleration. Impact acceleration will be different.
9/20/2005 3:59:38 PM EDT
[#27]
atomicferret,

I have the answers.  If you post yours, I will confirm whether your answers are correct.  I suspect you have the correct answers because (I will confirm for you) the bombs do impact with the same speed and angle.

Extra credit - if the point of release and the headings at time of release are the same for the two planes, how far apart do the bombs land?
9/20/2005 4:10:13 PM EDT
[#28]
... wow.  i think i stumbled into the wrong room. can somoeone point me to the BOTD room?


curious to see the answer.
9/20/2005 4:41:12 PM EDT
[#29]
Quoted:
v = dx/dy A (Acceleration is the level that gravity and friction act upon as a multiplier)

A having a vertical and horizontal component, being acted upon by gravity at around 9.8m/s2 for each projectile being released at +/- 15 degree increments. One will arc, the other will dive.

Its a fundamental time & distance equation, for which I have drunk too much wine at this time to contemplate.


Forward velocity will be equal in the absence of friction, being the forward derivative of acceleration. Impact acceleration will be different.



v=dx/dt
9/20/2005 6:13:22 PM EDT
[#30]
Both will hit the ground at 237.5 m/s at an angle of 57.8 degrees to the horizontal.  It will take the first bomb (+15) 6.9 s longer to hit the ground than the second (-15).
9/20/2005 7:39:05 PM EDT
[#31]
Posted by sd_norske

Both will hit the ground at 237.5 m/s at an angle of 57.8 degrees to the horizontal.



DING DING DING!!! We have a winner.
9/21/2005 6:34:27 PM EDT
[#32]
Quoted:
Posted by sd_norske

Both will hit the ground at 237.5 m/s at an angle of 57.8 degrees to the horizontal.



DING DING DING!!! We have a winner.

Yeah, I was laying in bed last night going over the day and I realized i didnt account for altitutde gained by the plane/bomb at the positive 15.

Honest error, HANG ME!.
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