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AR15.COM
5/17/2006 4:58:35 PM EDT
My brain is not up to speed.  My daughter has a simple algebra problem but naturally being in high math she can't remember how to figure this out and I can't remember how to set up this problem.

We're not asking someone to solve this equation for us just help us right it as an equation so we [her] can figure it out.  

Its a story problem:

Sally is going to college 320 miles away.  Her dad is taking her furniture in a moving van and she'll be driving her car.  Her dad can only drive 55 mph while Sally can drive 65 mph.  Sally gives her Dad a 30 minute head start.  How far from home will she be before catching up with him?

5/17/2006 5:01:05 PM EDT
[#1]
ETA:
read it backwards
5/17/2006 5:03:15 PM EDT
[#2]
yea set the problem up and read it backwards, I can solve it and put up the equation

the distance to college is to throw you off, pay no att.  you know how fast each is going so when will she catch up to him
5/17/2006 5:03:56 PM EDT
[#3]
distance = rate * time

dad = (55mph * 0.5hr) + (55mph * T)
sally = 65mph * T

set dad = to sally and solve for T

then plug T back into the equations to get the distances traveled.

ETA:  it's been a long day at work, and i still have about 4 hours to go....i think this is like half of it...probably not though.
5/17/2006 5:04:10 PM EDT
[#4]
27.5 miles, but I can't show my work
5/17/2006 5:06:32 PM EDT
[#5]

Quoted:
distance = rate * time

dad = (55mph * 0.5hr) + (55mph * T)
sally = 65mph * T

set dad = to sally and solve for T

ETA:  it's been a long day at work, and i still have about 4 hours to go....i think this is like half of it...probably not though.




[golfclap] that was quick [/golfclap]
5/17/2006 5:11:12 PM EDT
[#6]
hey, i think my foggy math actually worked....

27.5 miles + (55*T) = 65*T

27.5 = 10*T

2.75 = T

65mph * 2.75 hr = 178.75 miles  
5/17/2006 5:12:58 PM EDT
[#7]
and to check...

55mph*0.5hr + 55mph * 2.75hr = D

27.5 miles + 151.25miles = D

178.75 miles = D
5/17/2006 5:18:30 PM EDT
[#8]
2+2=4
5/17/2006 5:19:31 PM EDT
[#9]
All right she needs to show her work:

She needs to determine how far Dad goes in a minute - How far Sally goes in a minute too.
5/17/2006 5:21:13 PM EDT
[#10]
55 miles in an hour, divide 55/60, is miles per minute. ditto for 65 mph
5/17/2006 5:23:45 PM EDT
[#11]
hehehe

55miles per 1 hour

divide by 60

.916666667 miles per minute
or
.916666667 miles * 5280 feet (in a mile) = 4840 feet


Sally is the same way

65 miles per 1 hour

divide by 60 to get hours to minutes

1.08333333 miles per minute
which equals 5720 feet per minute
5/17/2006 5:34:17 PM EDT
[#12]
I just got 178.75 miles.

I'll post my work in a sec.
5/17/2006 5:40:25 PM EDT
[#13]
Sally = 65mph
Dad = 55mph

After the first half hour the Dad was 27.5 miles along (55mph*.5hrs).  Since Sally will be traveling 10mph faster then her father, it will take her 2.75hrs (10mph*2.75hrs= 27.5miles).  She was traveling at 65 for 2.75hrs, so she went 178.75 miles.
5/17/2006 5:46:42 PM EDT
[#14]

Quoted:
Sally = 65mph
Dad = 55mph

After the first half hour the Dad was 27.5 miles along (55mph*.5hrs).  Since Sally will be traveling 10mph faster then her father, it will take her 2.75hrs (10mph*2.75hrs= 27.5miles).  She was traveling at 65 for 2.75hrs, so she went 178.75 miles.



But wouldn't Dad continue traveling?  
5/17/2006 5:50:23 PM EDT
[#15]
yes the dad will, but the way he computed was to have dad "stop", and sally to continue on at 10mph, since that is the difference in speed.

ETA ""
5/17/2006 6:15:18 PM EDT
[#16]
The way speeddemon11L setup up the formula is probably the way the teacher would want to see it.  My way was just a little less confusing, atleast to me.
5/17/2006 7:16:39 PM EDT
[#17]
e = mc2