Warning

 

Close
Confirm Action

Are you sure you wish to do this?

Cancel Confirm
AR15.COM
7/23/2005 6:46:10 AM EDT
Find the probability of the result using the normal curve approximation to the bimominal distribution.
240 or more heads out of 500 coin tosses

What am I doing wrong?

mean= 250
std dev = square root of 500 (.50) (..50) =  11.18
z= 240- 250 divided by 11.18 = -.90
z=-.90= .3159
.5-.3159= .1841
.1841+.5= .6841   <-----------  should be the answer,   right?????????
7/23/2005 6:53:43 AM EDT
[#1]
I'm a little fuzzy on probability, but this line:

z=-.90= .3159

How does that one work?  
7/23/2005 7:02:08 AM EDT
[#2]

Quoted:
I'm a little fuzzy on probability, but this line:

z=-.90= .3159

How does that one work?  




You just look up the number off of the z table.
7/23/2005 7:13:11 AM EDT
[#3]
When you use the normal to approximate the binomial you must use the continuity correction by taking 239.5 instead of 240. This will slightly change your answer.

(239.5-250)/(125^.5) = -.93915, not -.90

Edited for typo
7/23/2005 9:30:48 AM EDT
[#4]

Quoted:
When you use the normal to approximate the binomial you must use the continuity correction by taking 239.5 instead of 240. This will slightly change your answer.

(239.5-250)/(125^.5) = -.93915, not -.90

Edited for typo




That is what I needed, thanks!!!!!
Close Join Our Mail List to Stay Up To Date! Win a FREE Membership!

Sign up for the ARFCOM weekly newsletter and be entered to win a free ARFCOM membership. One new winner* is announced every week!

You will receive an email every Friday morning featuring the latest chatter from the hottest topics, breaking news surrounding legislation, as well as exclusive deals only available to ARFCOM email subscribers.


By signing up you agree to our User Agreement. *Must have a registered ARFCOM account to win.