Posted: 8/29/2012 12:24:51 PM EDT
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Ok, I'm helping my cousin's niece tonight, specifically x/y intercept equations. It's been a while, but IIRC you set each one to 0 and then solve the equation if xy=3...substitute y with 0....x*0=3...0=3 Would that mean the intercept doesn't exist, would it be undefined, or am I doing something wrong?
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Quoted:
Ok, I'm helping my cousin's niece tonight, specifically x/y intercept equations. It's been a while, but IIRC you set each one to 0 and then solve the equation if xy=3...substitute y with 0....x*0=3...0=3 Would that mean the intercept doesn't exist, would it be undefined, or am I doing something wrong?y = 3 / x 1 = 3 3 = 1 6 = .5 right? |
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Quoted:
Ok, I'm helping my cousin's niece tonight, specifically x/y intercept equations. It's been a while, but IIRC you set each one to 0 and then solve the equation if xy=3...substitute y with 0....x*0=3...0=3 Would that mean the intercept doesn't exist, would it be undefined, or am I doing something wrong?Means you have some asymptotes. |
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xy=3; therefore y=x/3 Set x=0, get y=0 set y=0, get x=0 It intercepts both the x and y axes at 0 (i.e., this equation hits the center of the target). No. xy=3, therefore y=3/x and x=3/y No dividing by zero allowed. This isn't a line - maybe a hyperbola? |
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Convert it to the form of the slope equation and you can see that y-intercept would be zero: Slope equation => y = mx + (y intercept) Your equation in slope eq. form would be: y = 3/x + 0 What do you divide 3 by to get 0? I just said the y-intercept in the slope form eq. is valueless. Y would go to infinity if you divide 3 by 0. |
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Convert it to the form of the slope equation and you can see that y-intercept would be zero: Slope equation => y = mx + (y intercept) Your equation in slope eq. form would be: y = 3/x + 0 What do you divide 3 by to get 0? Chuck Norris can do that. |
Would that mean the intercept doesn't exist, would it be undefined, or am I doing something wrong?

