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The answer is 87. 


Y = mx + b



Rise over Run


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Oddnumbered answers are in the back



I think #4 is y=2



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Four and six are kinda trick questions, but what was the problem solving 5?
ETA What did you get trying to solve 5? 

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Dear Karma, I have a list of people you missed...
MN, USA

Don't they explain it at the begining of the lesson?
Or google how to do it. 
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Slope intercept form is y=mx +b. Y is the height on your graph. M is the slope. X is your independent variable. And b is the height of the line where it crosses the y axis.
To find the slope find the ratio of the amount the line rises divided by the amount it "runs" or moves horizontally. In the case of a purely horizontal line the equation is y=height of line 


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"Bureau of Alcohol, Snuff, Firearms and Explosives" Google translator. @Everrest

Originally Posted By jh1990: Slope intercept form is y=mx +b. Y is the height on your graph. M is the slope. X is your independent variable. And b is the height of the line where it crosses the y axis. To find the slope find the ratio of the amount the line rises divided by the amount it "runs" or moves horizontally. In the case of a purely horizontal line the equation is y=height of line View Quote 

"Elephant copulation lasts only 20 seconds. This should make a lot of men feel better. " A.J. Jacobs

What is his level of participation in solving these problems? Sounds like you are the one doing the homework assignment.


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Proper arfcom math protocol is to only misunderstand/hate DIFFERENT ways of teaching mathematics. There is no call for a thread like this.



"Elephant copulation lasts only 20 seconds. This should make a lot of men feel better. " A.J. Jacobs

Do you even lift bro?



Originally Posted By QueenDeNile: I got b=0, m = 3+5 but the back of the book states: m= 2/3 b=0 & y = 2/3 so I obviously do not know what I'm doing! View Quote View All Quotes View All Quotes Originally Posted By QueenDeNile: Originally Posted By WhyTanFox: Four and six are kinda trick questions, but what was the problem solving 5? ETA What did you get trying to solve 5? I got b=0, m = 3+5 but the back of the book states: m= 2/3 b=0 & y = 2/3 so I obviously do not know what I'm doing! ETA: I tried to rewrite the last part to make it less confusing, but I'm not sure that I succeeded. What I mean is that a line with a positive slope of greater than one will be steeper than 45 deg. and rise from left to right. A line with a slope of less than 1 (think of numbers on the number line, 2 is less than 1) will fall from left to right, and be steeper than 45 deg.



Originally Posted By Everrest:
Graphs Using SlopeIntercept Form http://www.youtube.com/watch?v=9wOalujeZf4 View Quote That video is doing a much better job explaining it than I would. 

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4)
Y Intercept.... 2 Equation y = 0x + 2 y = 2 5) Y Intercept........ 0 Equation y = (2/3)x +0 y = (2/3)x 6) Y Intercept.......NONE Equation x = 2 Whenever these is a horizontal, or a vertical line it means that either X or Y is the same for all values of Y or X. So for number 6, X will always be 2 no matter what value of Y. How can this be? Y in the equation is multiplies by 0 so whatever number you put in the equation, the Y value will never effect the outcome. 


Whythefox you did well. Thank you.


"Elephant copulation lasts only 20 seconds. This should make a lot of men feel better. " A.J. Jacobs


m is the slope.
b is the y intercept. Slope intercept form is y=mx+b. Problem 4 Lets find the Y intercept (outside of just looking at it). We need to find the equation as it passes through the points, 2,2 (x1,y1) and 2,2 (x2,y2) We know Y = 2 at a value of X = 0. Slope formula is m = (y1)  (y2) / (x1)  (x2) m = (2  2) / (2  2) m = 0 / 4 m = 0 Now we know the slope is 0. Find y intercept (b) where the slope is 0 (m, which we figured out above) and for point 2,2 (any point on line) y=mx+b 2 = 0*2 + b 2 = b b = 2 Now solve the equation. y = mx+b y = 0x + 2 The equation in this case will simply be y = 2. Thus: Your y intercept is 2 Your slope is 0 Your equation is y = 2 


288



Would you like me to walk through the rest of the problems in the same way I did above or have you received enough information?



Take two points to find the slope.
Suppose the points are (x1,y1) and (x2,y2). Then, the slope is m=(y2y1)/(x2x1). The point intercept form of a linear curve is y=mx+b. You know m. Now pick a point, such as (x1,y1) and plug it in. y1=mx1+b. Solve for b. b=y1mx1. Now you have m and b. Write out the linear curve. y=mx+b. Check your work by plugging in x2 and making sure that you get y2. ETA: Let me know if this is not clear. If not, then I will type it up in LaTex so it looks nice and send it to you via IM. 

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Originally Posted By Fieldgeek: Would you like me to walk through the rest of the problems in the same way I did above or have you received enough information? View Quote I've got it, thank you! I didn't understand the slope but I've got it. I haven't done this in 30 years though so more than likely I'll struggle tomorrow. 

"Elephant copulation lasts only 20 seconds. This should make a lot of men feel better. " A.J. Jacobs

To find the best fit line you need to use the "least squares method" and calculate the R^2 value.
Excel can do this for you. 


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