Posted: 11/4/2015 1:39:00 PM EDT
|
You want to play the Powerball once per week. To do so, you can either pick five numbers and the Powerball number on your own, or have the ticket machine randomly pick them for you.
Do you have a better chance of picking (and staying with the same) numbers every week or do you have a better chance having the machine pick them randomly for you each week? Or, does it not matter? |
|
Quoted:
You want to play the Powerball once per week. To do so, you can either pick five numbers and the Powerball number on your own, or have the ticket machine randomly pick them for you. Do you have a better chance of picking (and staying with the same) numbers every week or do you have a better chance having the machine pick them randomly for you each week? Or, does it not matter? not very good at statistics are you? |
|
Quoted:
From a news report I saw on the lottery a while back, you're much more likely to win with random quick pick numbers. It was a huge number, like 80% or something, that won with quick picks. Is that assuming that an equal number of people use the random option as do pick their own? I would guess that most people pick random numbers because it would be easier, although I don't play the lottery so that's pure speculation. |
|
Quoted:
Is that assuming that an equal number of people use the random option as do pick their own? I would guess that most people pick random numbers because it would be easier, although I don't play the lottery so that's pure speculation. Quoted:
Quoted:
From a news report I saw on the lottery a while back, you're much more likely to win with random quick pick numbers. It was a huge number, like 80% or something, that won with quick picks. Is that assuming that an equal number of people use the random option as do pick their own? I would guess that most people pick random numbers because it would be easier, although I don't play the lottery so that's pure speculation. That's probably the case. There is no statistical difference between picking 1 2 3 4 5 every week or picking 5 random numbers every week. |
|
There may be a slight mathematical difference, but I'd say there's no practical difference in which method you choose. The odds of winning are so tiny that it boils down to pure luck as to who and when the Powerball is hit.
ETA: I guess I was considering the odds that other players would choose the same numbers too, or get randomly selected those numbers, in which case other gambler's behavior would come into play as well. But from a straight "pick 6 numbers and see what gets drawn out of a hat", then I suppose the statistical odds of being correct are the same either way. |
|
I thought this was an interesting question. Saw a news report on a guy in Florida who makes all his income in lottery winnings. He plays all the scratch-off as well as the Powerball type games.
One of his "secrets to success" is that he always plays the same numbers. I know that the odds are identical either way. Out of curiosity, I just ran a quick scenario in Excel. Two columns...random/random and fixed/random, for 1000 tries. In the random/random trial, 108 of the picks were identical. In the fixed/random trial, 107 of the picks were identical. |
|
Quoted:
At first thought , sticking with one number would seem to give better odds but I don't think that's right. It is a random number. Not like it will eventually run through all numbers. I say it makes no difference. The number has the same odds in each trial. If the odds are 1,000,000:1 against your number in one trial, they will be 1,000,000:1 in every trial. If you lose 999,999 lottery picks, the odds will still be 1,000,000:1 against your number on the 1,000,000th pick. |
|
Quoted:
That's probably the case. There is no statistical difference between picking 1 2 3 4 5 every week or picking 5 random numbers every week. Quoted:
Quoted:
Quoted:
From a news report I saw on the lottery a while back, you're much more likely to win with random quick pick numbers. It was a huge number, like 80% or something, that won with quick picks. Is that assuming that an equal number of people use the random option as do pick their own? I would guess that most people pick random numbers because it would be easier, although I don't play the lottery so that's pure speculation. That's probably the case. There is no statistical difference between picking 1 2 3 4 5 every week or picking 5 random numbers every week. I know because math but I bet if you check all the lotteries of the world, and all their winning numbers, you won't find 12345(6) has ever been picked. I would almost also bet that it has never been any other complete consecutive number draw. I know what math says but... |
|
Quoted:
I know because math but I bet if you check all the lotteries of the world, and all their winning numbers, you won't find 12345(6) has ever been picked. I would almost also bet that it has never been any other complete consecutive number draw. I know what math says but... Quoted:
Quoted:
Quoted:
Quoted:
From a news report I saw on the lottery a while back, you're much more likely to win with random quick pick numbers. It was a huge number, like 80% or something, that won with quick picks. Is that assuming that an equal number of people use the random option as do pick their own? I would guess that most people pick random numbers because it would be easier, although I don't play the lottery so that's pure speculation. That's probably the case. There is no statistical difference between picking 1 2 3 4 5 every week or picking 5 random numbers every week. I know because math but I bet if you check all the lotteries of the world, and all their winning numbers, you won't find 12345(6) has ever been picked. I would almost also bet that it has never been any other complete consecutive number draw. I know what math says but... Georgia has a Cash 3 lotto which is 3 numbers, 1-10. They've had consecutive draws multiple times. 
|
|
Quoted:
From a news report I saw on the lottery a while back, you're much more likely to win with random quick pick numbers. It was a huge number, like 80% or something, that won with quick picks. According to Powerball's own website, the percentage of winners who used random numbers is almost exactly equal to the percentage of tickets sold which use random numbers. And, unless the game is rigged, playing last week's winning numbers is just as likely to win you the jackpot as any other set of numbers. I have encountered two sorts of people when I explain that to them---type one insists that I am wrong and that it is impossible for the winning numbers to be the same two drawings in a row, while type twos seem to suddenly grasp the relative futility of being a regular lottery player. Type ones far outnumber type twos, of course. |
|
Quoted:
Doesn't matter. I still have a 0% chance of winning. Nah, you have a better chance than zero. I mean, someone could buy a ticket with the winning numbers, but drop it to the ground, where you could find it walking along, or it could get picked up by a gust of wind of blown into the open window of your vehicle as you drive. I mean, the chances of that happening are pretty darn small, but not all that smaller than the odds of you actually buying the winning ticket. |
|
Quoted:
You want to play the Powerball once per week. To do so, you can either pick five numbers and the Powerball number on your own, or have the ticket machine randomly pick them for you. Do you have a better chance of picking (and staying with the same) numbers every week or do you have a better chance having the machine pick them randomly for you each week? Or, does it not matter? You are more likely to get killed driving to buy the tickets. 
|
|
Quoted:
You are more likely to get killed driving to buy the tickets. Quoted:
Quoted:
You want to play the Powerball once per week. To do so, you can either pick five numbers and the Powerball number on your own, or have the ticket machine randomly pick them for you. Do you have a better chance of picking (and staying with the same) numbers every week or do you have a better chance having the machine pick them randomly for you each week? Or, does it not matter? You are more likely to get killed driving to buy the tickets. 
https://www.youtube.com/watch?v=Y6MQUaXFfLY |
|
Quoted:
I know because math but I bet if you check all the lotteries of the world, and all their winning numbers, you won't find 12345(6) has ever been picked. I would almost also bet that it has never been any other complete consecutive number draw. I know what math says but... Quoted:
Quoted:
Quoted:
Quoted:
From a news report I saw on the lottery a while back, you're much more likely to win with random quick pick numbers. It was a huge number, like 80% or something, that won with quick picks. Is that assuming that an equal number of people use the random option as do pick their own? I would guess that most people pick random numbers because it would be easier, although I don't play the lottery so that's pure speculation. That's probably the case. There is no statistical difference between picking 1 2 3 4 5 every week or picking 5 random numbers every week. I know because math but I bet if you check all the lotteries of the world, and all their winning numbers, you won't find 12345(6) has ever been picked. I would almost also bet that it has never been any other complete consecutive number draw. I know what math says but... You won't find millions of other combinations either... like 12-15-34-21-5-19 (maybe... I didn't look this crap up). It just doesn't look as nice and orderly as 123456 but it's just as unlikely to be picked. Nothing at all makes an unordered number any more likely to be picked. When you fully understand this you understand just how unlikely it is that your number is picked as the winner. |
|
If all you want to do is win, pick whatever you want. All combinations are equally likely. Quick pick, birthdays, sequences, it doesn't matter.
If you want to maximize your winnings you would want to avoid combinations that other people are likely to choose. I don't know if any data has been released on this, but I would guess that past winners, straight sequences and the numbers 1-31 are probably over-represented. |
|
Quoted:
If all you want to do is win, pick whatever you want. All combinations are equally likely. Quick pick, birthdays, sequences, it doesn't matter. If you want to maximize your winnings you would want to avoid combinations that other people are likely to choose. I don't know if any data has been released on this, but I would guess that past winners, straight sequences and the numbers 1-31 are probably over-represented. That makes literally zero sense |
|
Quoted:
From a news report I saw on the lottery a while back, you're much more likely to win with random quick pick numbers. It was a huge number, like 80% or something, that won with quick picks. Logic fail; one method is not better than the other. If 80% of the winners are from "quick pick" it is because 80% of the tickets sold are quick pick :-) |
|
Quoted:
Nah, you have a better chance than zero. I mean, someone could buy a ticket with the winning numbers, but drop it to the ground, where you could find it walking along, or it could get picked up by a gust of wind of blown into the open window of your vehicle as you drive. I mean, the chances of that happening are pretty darn small, but not all that smaller than the odds of you actually buying the winning ticket. Quoted:
Quoted:
Doesn't matter. I still have a 0% chance of winning. Nah, you have a better chance than zero. I mean, someone could buy a ticket with the winning numbers, but drop it to the ground, where you could find it walking along, or it could get picked up by a gust of wind of blown into the open window of your vehicle as you drive. I mean, the chances of that happening are pretty darn small, but not all that smaller than the odds of you actually buying the winning ticket. Yep, I figure the difference between the odds of me finding the winning lottery ticket on the sidewalk and actually purchasing a winning lottery ticket is statistically insignificant. Though, I did win a car in a raffle this week, so I guess it IS true somebody does have to win.
|
|
Quoted:
That makes literally zero sense Quoted:
Quoted:
If all you want to do is win, pick whatever you want. All combinations are equally likely. Quick pick, birthdays, sequences, it doesn't matter. If you want to maximize your winnings you would want to avoid combinations that other people are likely to choose. I don't know if any data has been released on this, but I would guess that past winners, straight sequences and the numbers 1-31 are probably over-represented. That makes literally zero sense Splitting your winnings with other players who chose the same numbers as you greatly reduces the expected value of your bet. Let's simplify it, say you're betting on a coin flip. Heads or tails. At the end of the flip $1.00 is paid, split evenly among everyone who bet correctly. There are two people playing, you and one other person. There are 4 possible ways the two of you can lay your bets, HH, TT, HT, and TH. There are two scenarios you need to calculate: when you bet with the other player, and when you bet differently. If you bet with the other person, your expected value of your bet is (.5)*($0.50) + (.5)*($0.00), which equals $0.25. If you each bet differently, your expected value would be (.5)*($1.00) + (.5)*($0.00), or $0.50. In this game, you'll win twice as much money in the long run if you can guess what the other person is going to choose, and choose the opposite. In the lottery, you can pick 1-2-3-4-5-6 which 50 other people have picked, or pick something more random like 19-23-32-34-46-48 and be the only person to do so. Both numbers are equally likely to be drawn. With the first you share the jackpot with 50 people, and with the other you keep it to yourself. You maximize your winnings by picking an unpopular number. |
|
Quoted:
Splitting your winnings with other players who chose the same numbers as you greatly reduces the expected value of your bet. Let's simplify it, say you're betting on a coin flip. Heads or tails. At the end of the flip $1.00 is paid, split evenly among everyone who bet correctly. There are two people playing, you and one other person. There are 4 possible ways the two of you can lay your bets, HH, TT, HT, and TH. There are two scenarios you need to calculate: when you bet with the other player, and when you bet differently. If you bet with the other person, your expected value of your bet is (.5)*($0.50) + (.5)*($0.00), which equals $0.25. If you each bet differently, your expected value would be (.5)*($1.00) + (.5)*($0.00), or $0.50. In this game, you'll win twice as much money in the long run if you can guess what the other person is going to choose, and choose the opposite. In the lottery, you can pick 1-2-3-4-5-6 which 50 other people have picked, or pick something more random like 19-23-32-34-46-48 and be the only person to do so. Both numbers are equally likely to be drawn. With the first you share the jackpot with 50 people, and with the other you keep it to yourself. You maximize your winnings by picking an unpopular number. Quoted:
Quoted:
Quoted:
If all you want to do is win, pick whatever you want. All combinations are equally likely. Quick pick, birthdays, sequences, it doesn't matter. If you want to maximize your winnings you would want to avoid combinations that other people are likely to choose. I don't know if any data has been released on this, but I would guess that past winners, straight sequences and the numbers 1-31 are probably over-represented. That makes literally zero sense Splitting your winnings with other players who chose the same numbers as you greatly reduces the expected value of your bet. Let's simplify it, say you're betting on a coin flip. Heads or tails. At the end of the flip $1.00 is paid, split evenly among everyone who bet correctly. There are two people playing, you and one other person. There are 4 possible ways the two of you can lay your bets, HH, TT, HT, and TH. There are two scenarios you need to calculate: when you bet with the other player, and when you bet differently. If you bet with the other person, your expected value of your bet is (.5)*($0.50) + (.5)*($0.00), which equals $0.25. If you each bet differently, your expected value would be (.5)*($1.00) + (.5)*($0.00), or $0.50. In this game, you'll win twice as much money in the long run if you can guess what the other person is going to choose, and choose the opposite. In the lottery, you can pick 1-2-3-4-5-6 which 50 other people have picked, or pick something more random like 19-23-32-34-46-48 and be the only person to do so. Both numbers are equally likely to be drawn. With the first you share the jackpot with 50 people, and with the other you keep it to yourself. You maximize your winnings by picking an unpopular number. Ok, now list all likely combinations for the lottery, not a coin flip 
and once you have your set, what % of the entire population would you be eliminating? Would it be worth it to leave those numbers out? |
|
Quoted:
Splitting your winnings with other players who chose the same numbers as you greatly reduces the expected value of your bet. Let's simplify it, say you're betting on a coin flip. Heads or tails. At the end of the flip $1.00 is paid, split evenly among everyone who bet correctly. There are two people playing, you and one other person. There are 4 possible ways the two of you can lay your bets, HH, TT, HT, and TH. There are two scenarios you need to calculate: when you bet with the other player, and when you bet differently. If you bet with the other person, your expected value of your bet is (.5)*($0.50) + (.5)*($0.00), which equals $0.25. If you each bet differently, your expected value would be (.5)*($1.00) + (.5)*($0.00), or $0.50. In this game, you'll win twice as much money in the long run if you can guess what the other person is going to choose, and choose the opposite. In the lottery, you can pick 1-2-3-4-5-6 which 50 other people have picked, or pick something more random like 19-23-32-34-46-48 and be the only person to do so. Both numbers are equally likely to be drawn. With the first you share the jackpot with 50 people, and with the other you keep it to yourself. You maximize your winnings by picking an unpopular number. Quoted:
Quoted:
Quoted:
If all you want to do is win, pick whatever you want. All combinations are equally likely. Quick pick, birthdays, sequences, it doesn't matter. If you want to maximize your winnings you would want to avoid combinations that other people are likely to choose. I don't know if any data has been released on this, but I would guess that past winners, straight sequences and the numbers 1-31 are probably over-represented. That makes literally zero sense Splitting your winnings with other players who chose the same numbers as you greatly reduces the expected value of your bet. Let's simplify it, say you're betting on a coin flip. Heads or tails. At the end of the flip $1.00 is paid, split evenly among everyone who bet correctly. There are two people playing, you and one other person. There are 4 possible ways the two of you can lay your bets, HH, TT, HT, and TH. There are two scenarios you need to calculate: when you bet with the other player, and when you bet differently. If you bet with the other person, your expected value of your bet is (.5)*($0.50) + (.5)*($0.00), which equals $0.25. If you each bet differently, your expected value would be (.5)*($1.00) + (.5)*($0.00), or $0.50. In this game, you'll win twice as much money in the long run if you can guess what the other person is going to choose, and choose the opposite. In the lottery, you can pick 1-2-3-4-5-6 which 50 other people have picked, or pick something more random like 19-23-32-34-46-48 and be the only person to do so. Both numbers are equally likely to be drawn. With the first you share the jackpot with 50 people, and with the other you keep it to yourself. You maximize your winnings by picking an unpopular number. You're not understanding probability. Just as it doesn't matter which numbers you pick (random pick) the probability of winning doesn't change (assuming you don't have perfect information) and equally so you have the same probability of picking the same numbers as someone else whether you pick randomly or pick your own. Comparing it to a coin flip is an awful comparison and simply put as long as the pot size is large enough, picking random numbers is sufficient for a +EV bet. |
|
The odds of winning do not depend on any particular method of picking the numbers. You pick or the computer picks; it is all the same odds.
What does matter is the odds of SHARING the jackpot. You picking the numbers increases your chances of sharing the prize with someone else because most people use dates (1-31) for their numbers. Thus, including the higher numbers in your choices, like the computer will do, will decrease your chances of sharing the prize. |
|
Quoted:
You're not understanding probability. Just as it doesn't matter which numbers you pick (random pick) the probability of winning doesn't change (assuming you don't have perfect information) and equally so you have the same probability of picking the same numbers as someone else whether you pick randomly or pick your own. Comparing it to a coin flip is an awful comparison and simply put as long as the pot size is large enough, picking random numbers is sufficient for a +EV bet. Quoted:
Quoted:
Quoted:
Quoted:
If all you want to do is win, pick whatever you want. All combinations are equally likely. Quick pick, birthdays, sequences, it doesn't matter. If you want to maximize your winnings you would want to avoid combinations that other people are likely to choose. I don't know if any data has been released on this, but I would guess that past winners, straight sequences and the numbers 1-31 are probably over-represented. That makes literally zero sense Splitting your winnings with other players who chose the same numbers as you greatly reduces the expected value of your bet. Let's simplify it, say you're betting on a coin flip. Heads or tails. At the end of the flip $1.00 is paid, split evenly among everyone who bet correctly. There are two people playing, you and one other person. There are 4 possible ways the two of you can lay your bets, HH, TT, HT, and TH. There are two scenarios you need to calculate: when you bet with the other player, and when you bet differently. If you bet with the other person, your expected value of your bet is (.5)*($0.50) + (.5)*($0.00), which equals $0.25. If you each bet differently, your expected value would be (.5)*($1.00) + (.5)*($0.00), or $0.50. In this game, you'll win twice as much money in the long run if you can guess what the other person is going to choose, and choose the opposite. In the lottery, you can pick 1-2-3-4-5-6 which 50 other people have picked, or pick something more random like 19-23-32-34-46-48 and be the only person to do so. Both numbers are equally likely to be drawn. With the first you share the jackpot with 50 people, and with the other you keep it to yourself. You maximize your winnings by picking an unpopular number. You're not understanding probability. Just as it doesn't matter which numbers you pick (random pick) the probability of winning doesn't change (assuming you don't have perfect information) and equally so you have the same probability of picking the same numbers as someone else whether you pick randomly or pick your own. Comparing it to a coin flip is an awful comparison and simply put as long as the pot size is large enough, picking random numbers is sufficient for a +EV bet. He's left pure statistics and has entered the realm of game theory. If, for whatever reason, you determine that half the numbers are more likely to be picked, then in a split-pot system you have a higher EV by picking from the less used numbers. |
|
Quoted:
He's left pure statistics and has entered the realm of game theory. If, for whatever reason, you determine that half the numbers are more likely to be picked, then in a split-pot system you have a higher EV by picking from the less used numbers. Quoted:
Quoted:
Quoted:
Quoted:
Quoted:
If all you want to do is win, pick whatever you want. All combinations are equally likely. Quick pick, birthdays, sequences, it doesn't matter. If you want to maximize your winnings you would want to avoid combinations that other people are likely to choose. I don't know if any data has been released on this, but I would guess that past winners, straight sequences and the numbers 1-31 are probably over-represented. That makes literally zero sense Splitting your winnings with other players who chose the same numbers as you greatly reduces the expected value of your bet. Let's simplify it, say you're betting on a coin flip. Heads or tails. At the end of the flip $1.00 is paid, split evenly among everyone who bet correctly. There are two people playing, you and one other person. There are 4 possible ways the two of you can lay your bets, HH, TT, HT, and TH. There are two scenarios you need to calculate: when you bet with the other player, and when you bet differently. If you bet with the other person, your expected value of your bet is (.5)*($0.50) + (.5)*($0.00), which equals $0.25. If you each bet differently, your expected value would be (.5)*($1.00) + (.5)*($0.00), or $0.50. In this game, you'll win twice as much money in the long run if you can guess what the other person is going to choose, and choose the opposite. In the lottery, you can pick 1-2-3-4-5-6 which 50 other people have picked, or pick something more random like 19-23-32-34-46-48 and be the only person to do so. Both numbers are equally likely to be drawn. With the first you share the jackpot with 50 people, and with the other you keep it to yourself. You maximize your winnings by picking an unpopular number. You're not understanding probability. Just as it doesn't matter which numbers you pick (random pick) the probability of winning doesn't change (assuming you don't have perfect information) and equally so you have the same probability of picking the same numbers as someone else whether you pick randomly or pick your own. Comparing it to a coin flip is an awful comparison and simply put as long as the pot size is large enough, picking random numbers is sufficient for a +EV bet. He's left pure statistics and has entered the realm of game theory. If, for whatever reason, you determine that half the numbers are more likely to be picked, then in a split-pot system you have a higher EV by picking from the less used numbers. He understands it just fine. he's talking about expected value of your prize, not "probability of winning". |
|
Quoted:
You're not understanding probability. Just as it doesn't matter which numbers you pick (random pick) the probability of winning doesn't change (assuming you don't have perfect information) and equally so you have the same probability of picking the same numbers as someone else whether you pick randomly or pick your own. Comparing it to a coin flip is an awful comparison and simply put as long as the pot size is large enough, picking random numbers is sufficient for a +EV bet. I didn't say that the probability of winning changes. I said that the amount you win(or lose) changes. I do not believe that all lottery numbers are picked with equal frequency. (Edited for clarity: I mean the numbers the players pick, not the numbers drawn by the state) A portion of lottery players pick numbers that represent birthdays and anniversaries. And here's a headline for the UK lottery: 10,000 people are picking 1,2,3,4,5,6 every single week. The coin flip is simplified to demonstrate the concept of how splitting a prize affects your expected value, and it's not a bad comparison. A coin is a d2. A normal six-sided die is a d6. The lottery is a d(tens of millions). The odds and values will change, but he calculations will work the same. |
|
Quoted:
The answers are I don't know and yes I think so. Quoted:
Quoted:
and once you have your set, what % of the entire population would you be eliminating? Would it be worth it to leave those numbers out? The answers are I don't know and yes I think so. The lottery has a negative expected value of playing. Eliminating popular numbers to increase your expected value has no real effect in this game because of the magnitude of the odds |
|
Quoted:
Georgia has a Cash 3 lotto which is 3 numbers, 1-10. They've had consecutive draws multiple times.
Quoted:
Quoted:
Quoted:
Quoted:
Quoted:
From a news report I saw on the lottery a while back, you're much more likely to win with random quick pick numbers. It was a huge number, like 80% or something, that won with quick picks. Is that assuming that an equal number of people use the random option as do pick their own? I would guess that most people pick random numbers because it would be easier, although I don't play the lottery so that's pure speculation. That's probably the case. There is no statistical difference between picking 1 2 3 4 5 every week or picking 5 random numbers every week. I know because math but I bet if you check all the lotteries of the world, and all their winning numbers, you won't find 12345(6) has ever been picked. I would almost also bet that it has never been any other complete consecutive number draw. I know what math says but... Georgia has a Cash 3 lotto which is 3 numbers, 1-10. They've had consecutive draws multiple times.
your odds on that are approaching 1 in 100. (actually 0.83% if my math is correct) |
|
Quoted:
your odds on that are approaching 1 in 100. (actually 0.83% if my math is correct) Quoted:
Quoted:
Georgia has a Cash 3 lotto which is 3 numbers, 1-10. They've had consecutive draws multiple times.
your odds on that are approaching 1 in 100. (actually 0.83% if my math is correct) It isn't |
|
Quoted:
It isn't Quoted:
Quoted:
Quoted:
Georgia has a Cash 3 lotto which is 3 numbers, 1-10. They've had consecutive draws multiple times.
your odds on that are approaching 1 in 100. (actually 0.83% if my math is correct) It isn't It is 1 in 120 to be exact. (3 choose 3)/(10 choose 3) |
|
Quoted:
It is 1 in 120 to be exact. (3 choose 3)/(10 choose 3) Quoted:
Quoted:
Quoted:
Quoted:
Georgia has a Cash 3 lotto which is 3 numbers, 1-10. They've had consecutive draws multiple times.
your odds on that are approaching 1 in 100. (actually 0.83% if my math is correct) It isn't It is 1 in 120 to be exact. (3 choose 3)/(10 choose 3) Um is this a different game? .1 x .1 x .1 ETA - we are both right. One is odds for a straight vs odds for a box. Different payouts, blah blah |
|
Quoted:
From a news report I saw on the lottery a while back, you're much more likely to win with random quick pick numbers. It was a huge number, like 80% or something, that won with quick picks. Because most tickets are purchased as quick picks. Correlation is not causation. |