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AR15.COM
1/16/2017 9:11:03 PM EDT
OK.

My math skills bottom out at estimating the number of beers left when 3 are taken from a 6-pack, so I need your help.

So here's the problem.

A group of 15 shots is fired at 100 METERS {109 yards for discussion} and extreme spread measures 4.563" center-to-center.  

What will that group measure at 100 YARDS?

Would it be accurate to simply reduce it by 8% and call it 4.198"?
1/16/2017 9:14:22 PM EDT
[#1]
1/16/2017 9:16:56 PM EDT
[#2]
4.563" * 100 / 109
1/16/2017 9:33:17 PM EDT
[#3]
0.115890201 yards
1/16/2017 9:40:54 PM EDT
[#4]
Is that picture a platypus, or chocolate lab?
1/16/2017 9:41:01 PM EDT
[#5]
You're doing it the hard way.

Go to a 100 yard range that's already measured off.

Have fun shooting the 15 shots group. Someone will have to measure the group though.

Drink all six beers afterwards. No math involved, just fun!
1/16/2017 9:43:02 PM EDT
[#6]
God damn common core math strikes again.
1/16/2017 9:54:26 PM EDT
[#7]
Quote History
Quoted:
4.563" * 100 / 109
View Quote


So I'm right?
1/16/2017 9:59:23 PM EDT
[#8]
Roughly 1.225E-17 light-years.
1/16/2017 10:03:27 PM EDT
[#9]
Quote History
Quoted:
Roughly 1.225E-17 light-years.
View Quote


Alas, I'm beginning to think we have no mathematicians.

The education system is worse than I thought...
1/16/2017 10:06:41 PM EDT
[#10]
No sense in blowing things out of proportion, OP.
1/16/2017 10:09:59 PM EDT
[#11]
I get 4.563" * 100 / 109 = 4.186.
Or, a little more accurately, since you measured your group to the nearest thousandth of an inch, 4.563" * 100 / 109.361 = 4.172.

You are very close.

Don't make the problem hard.  Just use the law of similar triangles.
(Group size at R1) = (Group size at R2) * R1 / R2, where R1 and R2 are the 2 ranges.
It is a very simple formula and there is no approximation.
1/16/2017 10:12:22 PM EDT
[#12]
Thought about typing the explanation about constant ratios using the tangent function of a right angle diagram but scotch and beer have sapped my determination.

Suffice to say if you draw your hypothetical as a right angle triangle using half your group size as the opposite side and 109 yards as the adjacent side, you can convert everything to inches and arrive at (2.2815/3924)=(x/3600) which tells you x=2.093119 which means your group at 100 yards would be equal to 4.186 inches.

Edit, should have read replies, already answered.
1/16/2017 10:13:06 PM EDT
[#13]


(assuming 914.4mm = 1 yard)

100 yards = 91.44m
so
0.9144 x 0.453 inches = 4.1724072 inches
that is the answer unless you want some other unit.
1/16/2017 10:14:31 PM EDT
[#14]
Wouldn't this be more of a trigonometry math problem than geometry?
1/16/2017 10:15:00 PM EDT
[#15]
3.6 MOA  (appx 3.75" @100yd)

Forgot DDMMSSSS conversion...
1/16/2017 10:15:18 PM EDT
[#16]
Quote History
Quoted:


Alas, I'm beginning to think we have no mathematicians.

The education system is worse than I thought...
View Quote


...
1/16/2017 10:16:20 PM EDT
[#17]
I'm going to throw in a little twist.*

Bullets do not fly completely straight.  They have a bit of spiraling, and this is why groups are shaped the way they are.  Now, depending on the size and rate of spiral, the group you would have shot at 100 yards will not be perfectly proportional.  It could be larger or smaller than calculated.  It depends on where the bullets were at 100 yards in their precession.


*Pun fully intended.
1/16/2017 10:19:29 PM EDT
[#18]
Quote History
Quoted:


Alas, I'm beginning to think we have no mathematicians.

The education system is worse than I thought...
View Quote

Just because you didn't think of it first, asshole.

The answer is correct.  The OP didn't specify units, so why not have some fun?
BTW, I took 600-level math courses to fill in credits during my MSME.  I mostly just showed up for exams, and aced the classes.
1/16/2017 10:20:33 PM EDT
[#19]
Quote History
Quoted:
4.563" * 100 / 109
View Quote
This, unless the shots were fired from a treadmill.
1/16/2017 10:25:05 PM EDT
[#20]
Attached File
1/16/2017 10:27:50 PM EDT
[#21]
Thanks for the actual help, and thanks for the comic relief otherwise.  

I approached it differently.

I decided to simply calculate the MOA at the range shot.

So....

Using 1.047 as "1 MOA" at 100 YARDS, the formula appears to be this:

{1.047/100} X 109.361 which is the actual # of yards in 100 meters = 1.145.

Then I simply take the group size minus bullet diameter / 1.145 to get the MOA.

Thanks for all your help.

1/16/2017 10:29:41 PM EDT
[#22]
YELLOW!!! ...





...
1/16/2017 10:30:11 PM EDT
[#23]
similar triangles bruh

1/16/2017 10:31:35 PM EDT
[#24]
Quote History
Quoted:
Wouldn't this be more of a trigonometry math problem than geometry?
View Quote

Newp. Similar triangles is definitely geometry.
1/16/2017 10:34:40 PM EDT
[#25]
4.6(100)/109 = 4.2

You'll need special equipment to measure past two decimal places.  One place to the right is sufficient.
1/16/2017 10:42:18 PM EDT
[#26]
Quote History
Quoted:
Wouldn't this be more of a trigonometry math problem than geometry?
View Quote
Differential Equations. 
1/16/2017 10:43:27 PM EDT
[#27]
Quote History
Quoted:
Differential Equations. 
http://web.stanford.edu/~meehan/xyz/traj3.gif
View Quote


Don't forget the coriolis effect.
1/16/2017 11:11:47 PM EDT
[#28]


Keep in mind it's been nearly two decades since trig class and I'm half drunk. There are probably rounding errors (damned sig figs).
1/17/2017 12:14:24 AM EDT
[#29]
Quote History
Quoted:
http://i.imgur.com/oHt7Cgn.png

Keep in mind it's been nearly two decades since trig class and I'm half drunk. There are probably rounding errors (damned sig figs).
View Quote


It's not 109 yards though. 100m = 109.361y.

That's enough to throw OP off by almost 0.02in.

I'm just kidding around. AeroE and others have pointed out what's probably "close enough"

There are several ways to solve it with triangles, but the simplest is with a couple conversion numbers to use as multipliers.

If you want to pursue super ultra mega turbo precision just for making accurate estimates, use 0.9144 x your 100 meter group size in order to estimate what you should get at 100yds.
Conversely, if you're trying to estimate your group size at 100 meters based on what you measure at 100yds, simply multiply by 1.093613 and you'll have numbers that are probably finer than you need to know (within a hundredth of an inch).
1/17/2017 12:16:41 AM EDT
[#30]
Only 8, maybe ten people in the world could have made the shot.
1/17/2017 12:55:14 AM EDT
[#31]
Insufficient information variables left undefined.

At what distances were the cross winds, and there speed.
1/17/2017 1:51:25 AM EDT
[#32]
Also depends on what lattitude/longitude the bullet was shot at to calculate magnetic field effects. OP, did you shoot along the equator?
1/17/2017 1:57:50 AM EDT
[#33]
Quote History
Quoted:
http://i.imgur.com/oHt7Cgn.png

Keep in mind it's been nearly two decades since trig class and I'm half drunk. There are probably rounding errors (damned sig figs).
View Quote


I knew Trig would solve it.
1/17/2017 2:00:19 AM EDT
[#34]
4.2
1/17/2017 2:05:05 AM EDT
[#35]
Quote History
Quoted:

Just because you didn't think of it first, asshole.

The answer is correct.  The OP didn't specify units, so why not have some fun?
BTW, I took 600-level math courses to fill in credits during my MSME.  I mostly just showed up for exams, and aced the classes.
View Quote


If you're so smart, can you calculate a $24 transaction from say a credit card to pay for a team membership?
1/17/2017 11:57:24 AM EDT
[#36]
Quote History
Quoted:


If you're so smart, can you calculate a $24 transaction from say a credit card to pay for a team membership?
View Quote View All Quotes
View All Quotes
Quote History
Quoted:
Quoted:

Just because you didn't think of it first, asshole.

The answer is correct.  The OP didn't specify units, so why not have some fun?
BTW, I took 600-level math courses to fill in credits during my MSME.  I mostly just showed up for exams, and aced the classes.


If you're so smart, can you calculate a $24 transaction from say a credit card to pay for a team membership?
I can. Check out this spanking new avatar. HotBrass45 is jelly af.