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[ARCHIVED THREAD] - Algebra Question

Posted: 6/7/2006 4:05:01 PM EDT

Wife needs some help, and I'm math dumb!! We can't figure these out though they seem pretty simple.

X^4-16
X^2-4

and

Z^3-125
Z-5

Posted: 6/7/2006 4:14:55 PM EDT

[#1]

Quoted:
Wife needs some help, and I'm math dumb!! We can't figure these out though they seem pretty simple.

X^4-16
X^2-4

and

Z^3-125
Z-5

Been awhile but I'll give it a try...

x^4-16 factors into (x^2+4)(x^2-4), so youll end up with:
(x^2+4)(x^2-4)
x^2-4

Factor out a x^2-4 from the top and bottom and you end up with your answer of x^2+4.

screwed up the 2nd one, don't remember how to factor out the x^3-125..

Posted: 6/7/2006 4:16:01 PM EDT

[#2]

What does "^" mean in the expressions?

Posted: 6/7/2006 4:16:54 PM EDT

[#3]

Quoted:
What does "^" mean in the expressions?

It means the number after it is an exponet... x^2 is x squared.

Posted: 6/7/2006 4:17:16 PM EDT

[#4]

42!

Posted: 6/7/2006 4:17:32 PM EDT

[#5]

I'm totally dumb when it comes to algebra but i just got a 92% on my Quantitive Reasoning test today! When i am trying to teach myself a concept, i find this link helpful.

Webmath

Posted: 6/7/2006 4:17:44 PM EDT

[#6]

Thanks

Posted: 6/7/2006 4:20:17 PM EDT

[#7]

Therefor the sum of 85+2= ?

Posted: 6/7/2006 4:24:35 PM EDT

[#8]

doesn't x^4-16 factor to (x^2+4)(x^2-4)?

Posted: 6/7/2006 4:27:01 PM EDT

[#9]

Quoted:
doesn't x^4-16 factor to (x^2+4)(x^2-4)?

Oops

Yes it does

Posted: 6/7/2006 4:27:10 PM EDT

[#10]

Quoted:
doesn't x^4-16 factor to (x^2+4)(x^2-4)?

Yeah and the answer is x^2+4, right...

Posted: 6/7/2006 4:29:09 PM EDT

[#11]

Quoted:
doesn't x^4-16 factor to (x^2+4)(x^2-4)?

Yup. So (x^4-16)/(x^2-4) = x^2+4

ETA: Beateb by two minutes. Danged dialup...

Posted: 6/7/2006 4:32:15 PM EDT

[#12]

Quoted:
Quoted:
doesn't x^4-16 factor to (x^2+4)(x^2-4)?

Yup. So (x^4-16)/(x^2-4) = x^2+4

ETA: Beateb by two minutes. Danged dialup...

I'll let you take the 2nd one

Posted: 6/7/2006 4:46:45 PM EDT

[#13]

I can't remember how to factor cubes

Posted: 6/7/2006 4:48:13 PM EDT

[#14]

z^3-125 = (z-5)(z+5)(z-5)

5*5*5=125

z*z*z = z^3

so...

(z-5)(z+5)(z-5)/z-5 = (z-5)(z+5) = z^2-25

Posted: 6/7/2006 4:52:54 PM EDT

[#15]

I cheated
http://library.thinkquest.org/20991/alg2/polyf.html

I knew a z-5 would come out somehow due to it being given away with the division, but forgot exactly


z^3-125     (z-5)(z^2 +5z +25)
-------- = -------------------  =  z^2 +5z +25
z-5              z-5

Posted: 6/7/2006 4:53:26 PM EDT

[#16]

Quoted:
Wife needs some help, and I'm math dumb!! We can't figure these out though they seem pretty simple.

X^4-16
X^2-4

and

Z^3-125
Z-5

First problem - factor the numerator to (x^2+4)(x^2-4) and then divide. Result:x^2+4
Second problem - edited to add - see giggetty's sol'n above.

Posted: 6/7/2006 4:55:16 PM EDT

[#17]

uhoh flopped the - too many times...

Posted: 6/7/2006 5:00:05 PM EDT

[#18]

Z^3-125 factors to (z-5)(z^2+5z+25)

(z-5)(z^2+5z+25)=
z-5

Z^2+5z+25

But I dropped out in da fifh grade

Posted: 6/7/2006 6:03:51 PM EDT

[#19]

Wife says thanks!

[ARCHIVED THREAD] - Algebra Question

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[ARCHIVED THREAD] - Algebra Question

[ARCHIVED THREAD] - Algebra Question