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Except that, In his case, the bigger drive wins.
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After watching another sci fy movie last night, I once again wonder why they add that planar ring around explosions in space. Wouldn't a space explosion simply be a spherical, expanding wave of gas and debris? Why does part of the explosion favor one plane over any other? And wouldn't it dissipate faster than a wave in the atmosphere since there's nothing for a shock wave to propagate through?
Which begs the question - how close would one of our notional missile warheads need to detonate to create significant damage?
And those space missiles wouldn't be able to aerodynamically steer themselves, and simply rotating about their axis wouldn't change their direction of travel. They would need significant vectored thrust to correct course if the target is evading. Or rotate and fire their main engine to correct course.
You know, it turns out the old asteroids and lunar lander games got the physics right.
You say that the missiles would need significant vectored thrust to correct their course if the target is evading. That’s not quite accurate. They only need more thrust than their target has. There is no drag in space, so once it is closing to intercept, it only has to match the target’s maneuvers. The target has no special advantages over the missile with regards to maneuverability, and could have significant disadvantages in regards to rotation rates and thrust to weight ratios. Especially if heavily loaded with cargo or fuel.
Except that, In his case, the bigger drive wins.
No. It’s a matter of thrust to mass ratio, and how much delta-v the missile has. The missiles would be built with a high thrust to weight ratio. The delta-v they carry would determine the range the missile is useful at. Longer ranges means more time for the target to use their more efficient engines. If the target can maneuver enough while the missile closes distance, it could run the missile out of delta-v, basically put itself on a trajectory that the missile cannot match.
Determining the optimal closing speed for the missile would likely involve making an estimate of the maximum acceleration of your target. A higher closing speed requires using more of the missile’s delta-v in the initial burn, and leaves less for maneuvering, but conversely, a lower closing speed means that your target has more time to maneuver, and you need more delta-v to match the target’s maneuvers. If you know exactly how much acceleration your target can achieve, then you have the missile burn towards the target until is has just over the delta-v remaining that your target can achieve if it were to go to maximum burn the entire time to intercept. Depending on the amount of fuel or cargo onboard the target (or if the target dumps cargo or propellant to improve their acceleration), it could have very different acceleration even compared to other ships of the same class.
This assumes that your target is not going to actively defend itself against your missile. If that were the case, you are likely going to want your missile to save additional delta-v for doing its own evasive maneuvers as it closes on the target.