User Panel
User Panel
User Panel
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Posted: 10/15/2020 11:01:48 PM EDT
Trying to make sure I understand how the left converts to the right.
I'm not positive on step 3 as I don't recall that rule in Algebra but it's the only thing that makes sense on how to get to the final result. Original equation and simplified solution:  My attempt (again not sure about step 3):  Thanks. |
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Posted: 10/16/2020 4:53:21 AM EDT
[#1]
I think that's right
(a - b) ^n / m^n = ((a - b) /m ) ^n You can always use small numbers to check this stuff ( 6-2)^2 / 2^2 = ( ( 6-2)/2) ^2 (4^2)/4 = 4 = (4/2)^2 = 4 |
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Posted: 10/16/2020 4:33:55 PM EDT
[#2]
That's right
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Posted: 10/17/2020 11:51:24 PM EDT
[#3]
Thanks guys.
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Posted: 10/17/2020 11:55:27 PM EDT
[#4]
Quote HistoryQuoted: I think that's right (a - b) ^n / m^n = ((a - b) /m ) ^n You can always use small numbers to check this stuff ( 6-2)^2 / 2^2 = ( ( 6-2)/2) ^2 (4^2)/4 = 4 = (4/2)^2 = 4 That's what I always do to check my work. |
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Posted: 10/19/2020 1:52:50 PM EDT
[#5]
Quote HistoryQuoted: That's what I always do to check my work. Quote HistoryQuoted: Quoted: I think that's right (a - b) ^n / m^n = ((a - b) /m ) ^n You can always use small numbers to check this stuff ( 6-2)^2 / 2^2 = ( ( 6-2)/2) ^2 (4^2)/4 = 4 = (4/2)^2 = 4 That's what I always do to check my work. Small is relative. And while 1 and 2 are 'small' they can also cause discontinuities in certain functions. Like dividing by x when x is 0 or the denominator is 'x-1.' Anytime you end sup with x-n in a denominator you have to be aware that the calculation is NOT valid when x=n. You have a singularity at that value. |
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