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AR15.COM
8/29/2009 10:46:12 PM EDT
I haven't taken algebra since High School, and that was a loooong time ago. I am having to retake intermediate algebra this semester in college since I have forgotten pretty much everything I learned all those years ago.

So, I have a problem in my homework that we didn't cover in class, and I can't find any info on how to handle it in the text book. All I need is a reminder.

The problem is this:

2[4-2(3-x)]-1=4[2(4x-3)+7]-25

IF I recall correctly, then you are supposed to work the problem from the inside out. Distribute your numbers to eliminate the parenthesis inside the brackets, then combine any like terms inside the brackets, then distribute any numbers outside the beginning of the brackets, then combine any like terms after the brackets.

Right?
8/29/2009 10:54:44 PM EDT
[#1]
dropped it into mathematica and it spit this out

-25 + 4[7 + 2 (-3 + 4 x)]
8/29/2009 10:55:06 PM EDT
[#2]
2 (8 -3) == (16 - 6)
8/29/2009 11:17:44 PM EDT
[#3]
x = 1 2/32ths
8/29/2009 11:29:19 PM EDT
[#4]
how about  x=16/28  or x=.571429
8/29/2009 11:32:37 PM EDT
[#5]
2[4-2(3-x)]-1 = 4[2(4x-3)+7]-25

2[4-(6-2x)]+24 = 4[(8x-6)+7]

2[-2+2x]+24 = 4[8x+1]

-4+4x+24 = 32x+4

4x+20 = 32x+4

16 = 28x

x = 16/28

x = .5714
8/29/2009 11:53:32 PM EDT
[#6]
x=87
8/30/2009 12:22:51 AM EDT
[#7]
Lots of help:

http://www.algebrahelp.com/calculators/equation/
8/30/2009 4:36:43 AM EDT
[#8]
Quoted:
2[4-2(3-x)]-1 = 4[2(4x-3)+7]-25

2[4-(6-2x)]+24 = 4[(8x-6)+7]

2[-2+2x]+24 = 4[8x+1]

-4+4x+24 = 32x+4

4x+20 = 32x+4

16 = 28x

x = 16/28

x = .5714


Give the man a chicken dinner.
8/30/2009 5:19:09 AM EDT
[#9]
use 4/7 as your answer.  

8/30/2009 5:26:55 AM EDT
[#10]
8/30/2009 5:29:18 AM EDT
[#11]



Quoted:


x = 1 2/32ths


Crazy Aussie math.


 
8/30/2009 5:33:34 AM EDT
[#12]
Quoted:

Quoted:
x = 1 2/32ths

Crazy Aussie math.  


Looking over my notes, I made an order mistake. Did a subtraction before a multiplication.

It's why I'm in law and not engineering school.