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AR15.COM
6/1/2003 6:00:24 AM EDT
A theorem both deep and profound,

States that every circle is round.

In a paper by 'storm

Where great insight is born,

A counterexample is found!
6/1/2003 6:07:36 AM EDT
[#1]
A fan of Paul Erdös?
6/1/2003 6:09:27 AM EDT
[#2]
I've read it 4 times and I get nothing.
Does this require drugs?
6/1/2003 6:11:39 AM EDT
[#3]
All I can think of is a Mobius strip.
6/1/2003 8:18:45 AM EDT
[#4]
The equation has no solution for non-zero integers x, y, and z if n is an integer greater than 2.

At the highest level, the proof is extremely simple to understand, since it follows from just 2 theorems: Theorem A: If there is a solution (x, y, z, n) to the Fermat equation, then the elliptic curve defined by the equation
is semistable but not modular.

Theorem B: All semistable elliptic curves with rational coefficients are modular.
6/1/2003 10:05:34 AM EDT
[#5]
Yes, but this is contradicted by Green's Theorem of the Plain: "The rain in Spain falls mainly on the plain."
6/1/2003 10:09:08 AM EDT
[#6]
I hate math
6/1/2003 12:19:05 PM EDT
[#7]

 Uhhh...  I'm like...  angry at numbers.  

6/1/2003 12:32:38 PM EDT
[#8]
Think about this:

a. The number of physicians in the US is 700,000
b. Accidental deaths caused by physicians each year is 120,000+
c. Accidental deaths per physician is 0.171 . ( US Dept. of Health & Human Services )
d. If you are a convicted felon and pass the State Medical Board exam, you can be a licensed, practicing physician when nobody else will give you a job.

Then think about this:

a. The number of gun owners in the US is 80,000,000 (thats 80 million)
b. The number of accidental gun deaths per year (all age groups) is 1,500
c. The number of accidental gun deaths per gun owner is .0000188 .
d. If you are a convicted felon, the State will put you in jail for having a gun.

Statistically, doctors are approximately 9,000 times more dangerous than gun owners.

FACT: NOT EVERYONE HAS A GUN, BUT EVERYONE HAS AT LEAST ONE DOCTOR.

Now don't you think it is odd that they are in Washington crying about the cost of their Malpractice insurance?

PS. As a public health measure I have withheld the statistics on Attorneys for fear that the shock could cause people to seek medical attention.



--------------------------------------------------------------------------------
6/1/2003 12:37:02 PM EDT
[#9]
"What if C-A-T really spelled DOG?" (Ogre in Revenge of the Nerds)
"Whoa that's deep Ogre!"
6/1/2003 1:04:01 PM EDT
[#10]
Quoted:
I've read it 4 times and I get nothing.
Does this require drugs?
View Quote


Three shots of whiskey (or equivalent) and you will be able to see that it is all irrelevant. Plus, you won't care.
6/1/2003 1:20:19 PM EDT
[#11]
From any gun related board with a population =>100:

xy=z

where:
x=number of members
y=0.97
z=number of feds, mjtf, state doj, agent provocateurs

6/1/2003 1:32:59 PM EDT
[#12]
ummmm, yeah, theres like, too many of them
6/1/2003 1:38:46 PM EDT
[#13]
I like the way you place things into context, Falcon2.
6/1/2003 1:54:39 PM EDT
[#14]

The following statement is false: The previous statement was true.

6/1/2003 2:01:07 PM EDT
[#15]
Quoted:
The equation has no solution for non-zero integers x, y, and z if n is an integer greater than 2.

At the highest level, the proof is extremely simple to understand, since it follows from just 2 theorems: Theorem A: If there is a solution (x, y, z, n) to the Fermat equation, then the elliptic curve defined by the equation
is semistable but not modular.

Theorem B: All semistable elliptic curves with rational coefficients are modular.
View Quote


The proof of Fermat's Last Thm follows.
6/1/2003 2:41:37 PM EDT
[#16]
I'm studying applied mathematics, and I'm not certain if I should be scared or glad that I don't know WTF realist is talking about.
6/1/2003 3:02:48 PM EDT
[#17]
Quoted:
The equation has no solution for non-zero integers x, y, and z if n is an integer greater than 2.

At the highest level, the proof is extremely simple to understand, since it follows from just 2 theorems: Theorem A: If there is a solution (x, y, z, n) to the Fermat equation, then the elliptic curve defined by the equation
is semistable but not modular.

Theorem B: All semistable elliptic curves with rational coefficients are modular.
View Quote




I think if you monitor that with Doppler radar and take the proctologist approach, everything should come out fine.
6/1/2003 3:39:17 PM EDT
[#18]
Quoted:
A theorem both deep and profound,

States that every circle is round.

In a paper by 'storm

Where great insight is born,

A counterexample is found!
View Quote


A square is 1/6 of a cube.[thinking]


How many circles to make a sphere?[slap]
6/1/2003 4:00:13 PM EDT
[#19]
Quoted:
Every square is 1/6 of a cube.[thinking]


How many circles to make a sphere?[slap]
View Quote


Four.

And I think you meant that there's six squares to make a cube.
6/1/2003 4:29:19 PM EDT
[#20]
Thanks, keep me honest.

I need more Math.