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AR15.COM
10/25/2010 5:25:28 PM EDT
cos(3x)=cos^3(x)-3sin^2(x)cos(x)



I got to:



cos(x) * (cos^2(x)-3sin^2(x))



Now I'm stumped. Stupid 3!


10/25/2010 5:28:17 PM EDT
[#1]
Quoted:
cos(3x)=cos^3(x)-3sin^2(x)cos(x)

I got to:

cos(x) * (cos^2(x)-3sin^2(x))

Now I'm stumped. Stupid 3!




DO IT.

Post results.

_MaH
10/25/2010 5:29:12 PM EDT
[#2]
Feh,

87, duh

ETA: Sorry forgot to carry the three, the correct answer is BR 549
10/25/2010 5:35:54 PM EDT
[#3]
Are you starting from cos(3x) or from cos^3(x) - 3 sin^2(x)cos(x)? I strongly suggest starting from cos(3x).
10/25/2010 5:39:24 PM EDT
[#4]
Work the left side of the equation.  Look into the double angle formulas for clues.
10/25/2010 5:42:22 PM EDT
[#5]



Quoted:


Work the left side of the equation.  Look into the double angle formulas for clues.


I know what the double angle identity for cos(2x) is, but does it work the same way for triple or quadruple angle identities? I don't know.



 
10/25/2010 6:00:14 PM EDT
[#6]
Quoted:

Quoted:
Work the left side of the equation.  Look into the double angle formulas for clues.

I know what the double angle identity for cos(2x) is, but does it work the same way for triple or quadruple angle identities? I don't know.
 


Yes.
10/25/2010 6:09:47 PM EDT
[#7]
I didnt realize it did. You can do it without any triple angle formula.

Extra ETA: Does it? Aren't we deriving a triple angle formula here?
10/25/2010 6:17:05 PM EDT
[#8]
(x + 2x) = 3x



I'm pretty proud of myself, it's been ~20 years since HS.
Is Schaum's still in print?
10/25/2010 6:18:59 PM EDT
[#9]
This thread might as well be in french.  Don't understand sheeitt.
10/25/2010 6:22:12 PM EDT
[#10]
I don't remember any trig identities like that.  wtf?  I can integrate it for you though .
10/25/2010 6:25:04 PM EDT
[#11]
Hmm...this one is stumping me a little.

I hate F-ing trig identities. Needless to say, Calculus isn't much fun either.

-D2V
10/25/2010 6:26:40 PM EDT
[#12]
Quoted:
Hmm...this one is stumping me a little.

I hate F-ing trig identities. Needless to say, Calculus isn't much fun either.

-D2V


Lies! I do it as a drinking game... damn college has screwed with my mind.
10/25/2010 6:27:05 PM EDT
[#13]



Quoted:



Quoted:




Quoted:

Work the left side of the equation.  Look into the double angle formulas for clues.


I know what the double angle identity for cos(2x) is, but does it work the same way for triple or quadruple angle identities? I don't know.

 




Yes.
So what about this?



cos(3x) = cos^3(x)-3sin^2(x)cos(x)



=cos(x) * (cos^2(x) - 3sin^2(x))



=cos(x) * (1-sin^2(x) -3(sin^2(x)))



=cos(x) * (1-3*sin^2(x)+sin^2(x))



=cos(x) * (1-3)



=cos(x) * (-3)



=cos(-3x)



=cos(3x)



I fucking hate these identities. They seem to through algebra out the window.



 
10/25/2010 6:28:43 PM EDT
[#14]
cos(a + b) = cos(a)cos(b) – sin(a)sin(b)


a=x
b=2x

just an idea.

10/25/2010 6:32:49 PM EDT
[#15]
Quoted:
Hmm...this one is stumping me a little.

I hate F-ing trig identities. Needless to say, Calculus isn't much fun either.

-D2V


I hate them too.  Lowered my grade from an A to a B.  But then I was trying to teach myself how to do them.  My teacher hardly spoke any English which did not help.
10/25/2010 6:33:30 PM EDT
[#16]



Quoted:


cos(a + b) = cos(a)cos(b) – sin(a)sin(b)





a=x

b=2x



cos(a+b) = cos (x+2x) = cos(3x)

....

you see where this is going.
I do, but it doesn't seem to fit right.



I have to make cos(3x) = cos^3(x)-3sin^2(x)cos(x)





 
10/25/2010 6:38:28 PM EDT
[#17]
Quoted:

Quoted:
cos(a + b) = cos(a)cos(b) – sin(a)sin(b)


a=x
b=2x

cos(a+b) = cos (x+2x) = cos(3x)
....
you see where this is going.
I do, but it doesn't seem to fit right.

I have to make cos(3x) = cos^3(x)-3sin^2(x)cos(x)

 


yeah i dont think I had the right identity. you may have to use more than one identity to get there too.
10/25/2010 6:39:04 PM EDT
[#18]



Quoted:



Quoted:

Hmm...this one is stumping me a little.



I hate F-ing trig identities. Needless to say, Calculus isn't much fun either.



-D2V




I hate them too.  Lowered my grade from an A to a B.  But then I was trying to teach myself how to do them.  My teacher hardly spoke any English which did not help.


My professor barely speaks English and brags that he feels it's his job to confuse us by giving us trick questions. I hate this asshole. I really do.



 
10/25/2010 6:41:42 PM EDT
[#19]
http://mathworld.wolfram.com/Multiple-AngleFormulas.html





















































 

































For , the multiple-angle formula can be derived as



























































































































(25)



(26)



(27)



(28)



(29)



(30)



The first few values are
















































(31)





this editor is broken.








 
10/25/2010 8:31:10 PM EDT
[#20]
Quoted:

Quoted:
cos(a + b) = cos(a)cos(b) – sin(a)sin(b)


a=x
b=2x

cos(a+b) = cos (x+2x) = cos(3x)
....
you see where this is going.
I do, but it doesn't seem to fit right.

I have to make cos(3x) = cos^3(x)-3sin^2(x)cos(x)

 

Identities needed: Sum Difference, Double Angle, Double Angle. (Distribution and simplify.)

Start left side as he suggested.

Any more and you'll be given the answer.