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AR15.COM
10/12/2010 11:28:40 AM EDT
I need some help with this problem.

|-3x+1/5|=6

Thus far I realize is it going to be +- 6 and I subtract 1/5 from each but I get an improper fraction or mixed number and dividing that by 3 doesn't really help me for plotting interval notation.
10/12/2010 11:38:36 AM EDT
[#1]
Is it an equality or inequality.  Interval notation is not that useful for equalities...
10/12/2010 11:39:07 AM EDT
[#2]
Quoted:
I need some help with this problem.

|-3x+1/5|=6

Thus far I realize is it going to be +- 6 and I subtract 1/5 from each but I get an improper fraction or mixed number and dividing that by 3 doesn't really help me for plotting interval notation.


|-3x+1/5| = 6
-3x+1/5 = +- 6
-3x = (+-6) - 1/5
-3x = +6 - 1/5 or -6 -1/5
-3x = +29/5 or -31/5
x = (+29/5)/-3 or (-31/5)/-3
x = -29/15 or +31/15

ETA interval notation:
[-29/15] U [31/15]
10/12/2010 11:40:01 AM EDT
[#3]
x=-10
10/12/2010 11:42:32 AM EDT
[#4]
Quoted:
x=-10


It's +1/5, not *1/5
10/12/2010 12:00:09 PM EDT
[#5]
Quoted:
I need some help with this problem.

|-3x+1/5|=6

Thus far I realize is it going to be +- 6 and I subtract 1/5 from each but I get an improper fraction or mixed number and dividing that by 3 doesn't really help me for plotting interval notation.


I always liked to do it with a double equality.

-6 = -3x+1/5 = 6
-31/5 = -3x = 29/5
31/15 = x =  -29/15
10/12/2010 12:03:57 PM EDT
[#6]
Could you square both sides and then take the square root?
10/12/2010 12:07:42 PM EDT
[#7]
after collage you will never need to know it again
10/12/2010 12:08:43 PM EDT
[#8]
Quoted:
Quoted:
I need some help with this problem.

|-3x+1/5|=6

Thus far I realize is it going to be +- 6 and I subtract 1/5 from each but I get an improper fraction or mixed number and dividing that by 3 doesn't really help me for plotting interval notation.


I always liked to do it with a double equality.

-6 = -3x+1/5 = 6
-31/5 = -3x = 29/5
31/15 = x =  -29/15

I'm liking this looks like something I can understand. So for another one such as |2x/3-2|>=7. Would I make the seven positive and negative. Add 2 to the seven. Then multiply it by 3 to get 2x>=9, and 2x<=-15 then divide by 2? My specific problem is when I multiply the 3 and the two x does it just become 2x or 6 x?
10/12/2010 12:34:07 PM EDT
[#9]
The only concern with the 3-column method is that you have to be careful not to confuse the left and right answers.

In the second example, it would be:

|2x/3-2|>7

-7 > 2/3*x - 2 > 7
-5 > 2/3*x > 9
-15/2 > x > 27/2

Note that you must flip the inequality on the left side to begin.  And don't confuse the answer with a window.  It's actually x > 27/2 OR x < -15/2