abc,acb,bca,bac,cab,cba
+
123,132,231,213,312,321
combine any set together and do the same thing.
abc123,abc132,abc231,etc.etc.
#c*12*
aw hell its been too long since i was in math class to know the exact formula.
assuming the characters could only be used once in any equasion, its a probabilities game
randomely selected, there are 6 probabilities for c(character)1, then ehatever C is in position 1 can't be in any other position, so there are only 5 C's to choose from in the second choice. etc,etc
6*5*4*3*2*1=720 for each C1
multiplie that thimes the nomber of possable C1's
720*6=4320
the # of possable C2's is equal to 5*4*3*2*1=120 for each C2 multiplie for each possable C2
120*5=600
keep doing this and you come up with
4*3*2*1=24*4=96
3*2*1=6*3=18
2*1=1*2=2
1=1*1=1
add 1+2+18+96+600+4320=5037 permutations. this is for ONE possable C1
so the possabilities of any set of # starting with A = 1 in 5037
multiplie this # times the # of possable C1's and you come up with 5037*6=30222 so the possabilitie of any permutation begining with A3 (for example) is 1 in 30222
multiplie this # times the # of possable C2's and you come up with 30222*5=151110
keep doing this and this is what you get.
151110*4=604440*3=1813320*2=3626640*1
or maby its *6-#of previouse C's
anyway you get the idea that it is a long mathematical equasion.. that you have to be einstien to really understand..