Posted: 10/13/2004 7:49:38 PM EST
[Last Edit: 10/13/2004 7:49:56 PM EST by ColonelKlink]
Im working with alternating infinite series shit for calculus three and I cant remember from calculus one why the limit of a negative integer with and exponent x that approaches infinity is undefined. I know it oscillates back and fourth so the limit doesnt exist, but does anyone know how to break it down mathematically to prove it?.
Thanks, Klink. 

I am Thor, Supreme Commander of the Asgard fleet. Your presence here is a violation of the Protected Planets Treaty and you must withdraw immediately.

Marine Aviation VMA(AW)224 .... Cherry Point, NC
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yes multiply by 4

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We speak English in the US son! And that right there is why I hate adv math... 


Edite, lol mis read, I am a dumb ass for give me. lease forgive lol
? 


Yes, mathematically speaking.
if you draw a graph of the function, and it represents asymtotes, then mathematically you could show that as each number approches the limit, but never touches it because 1 turns into .5, then .25, then one eigth and so on. it gets so close but never touches the limit because the fraction just gets cut in *half each time. hope this helps. 

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"Any you sumbitches calls me grandpa,.......... ...........I'll kill ya." 
doesn't seem like it can be broken down anymore. A^inf=inf (therefore, the lim as x approached inf = inf)



I was taught that if X=^5 then infinity is undefined...only if it appraoching X.


Common sense is a wonderful thing...it's just not common.

I am Thor, Supreme Commander of the Asgard fleet. Your presence here is a violation of the Protected Planets Treaty and you must withdraw immediately.

nevermind then. 

"T've got two guns, one for each of ya."
"Any you sumbitches calls me grandpa,.......... ...........I'll kill ya." 
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