Another calculus question

[ARCHIVED THREAD] - Another calculus question

Posted: 10/13/2004 8:49:38 PM EDT

Im working with alternating infinite series shit for calculus three and I cant remember from calculus one why the limit of a negative integer with and exponent x that approaches infinity is undefined. I know it oscillates back and fourth so the limit doesnt exist, but does anyone know how to break it down mathematically to prove it?.

Thanks,
Klink.

Posted: 10/13/2004 8:53:50 PM EDT

[#1]

yes multiply by 4

Posted: 10/13/2004 8:55:12 PM EDT

[#2]

Quoted:
Im working with alternating infinite series shit for calculus three and I cant remember from calculus one why the limit of a negative integer with and exponent x that approaches infinity is undefined. I know it oscillates back and fourth so the limit doesnt exist, but does anyone know how to break it down mathematically to prove it?.

Thanks,
Klink.

We speak English in the US son!

And that right there is why I hate adv math...

Posted: 10/13/2004 8:56:36 PM EDT

[#3]

Edite, lol mis read, I am a dumb ass for give me. lease forgive lol
?

Posted: 10/13/2004 8:57:52 PM EDT

[#4]

Yes, mathematically speaking.

if you draw a graph of the function, and it represents asymtotes, then mathematically you could show that as each number approches the limit, but never touches it because 1 turns into .5, then .25, then one eigth and so on.

it gets so close but never touches the limit because the fraction just gets cut in *half each time.

hope this helps.

Posted: 10/13/2004 8:57:56 PM EDT

[#5]

doesn't seem like it can be broken down anymore. A^inf=inf (therefore, the lim as x approached inf = inf)

Posted: 10/13/2004 9:01:22 PM EDT

[#6]

I was taught that if X=^5 then infinity is undefined...only if it appraoching X.

Posted: 10/13/2004 9:28:27 PM EDT

[#7]

Quoted:
doesn't seem like it can be broken down anymore. A^inf=inf (therefore, the lim as x approached inf = inf)

no what i am saying is that this

is undefined.

Posted: 10/13/2004 9:29:42 PM EDT

[#8]

Quoted:
Quoted:
doesn't seem like it can be broken down anymore. A^inf=inf (therefore, the lim as x approached inf = inf)

no what i am saying is that this
home.comcast.net/~colonelklink/lim.jpg

is undefined.

nevermind then.

[ARCHIVED THREAD] - Another calculus question

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