Posted: 3/31/2026 11:06:35 PM EDT
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Had a triangle with all three angles known and the base length. I could not locate a formula or formulas to calculate the height where the two angles met at the top. I solved it the hard way doing the rise per .001" of each bottom angle which were different degrees. Then divided the two, larger by smaller added one to the result divided that into the base and multiplied the result with the largest angle rise per .001" . But I know there is some written out formula easier to follow. Anyone know what it is because I could not locate one on the net when the three angles were different and only the base was known. Thanks for some direction. |
| Can you draw a line perpendicular to the long leg that hits the opposite angle? That should give you two right angle triangles to apply ye-ole a^2=b^2+c^2 |
Disclaimer - OP is bad at knowing things, and might catch on fire.
Vet - Op MMAMA
Every other species kills off their stupid......we cater to them. -- spin-drift
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Vet - Op MMAMA
Every other species kills off their stupid......we cater to them. -- spin-drift
Nobody ever called 911&said I just did something smart. -- TheFlynDutchman
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The only information is the three inside angles and the base length. No other lengths. Base is .125" top angle is 87.5 degrees , left angle is 22.5 , and the right is 70. No idea where the two angles intersect over the base, what distance point to draw a 90 degree to max height above the base, or the height until it is solved. No side lengths no height length only length is the base. I am sure there is a formula or two to do it but I can't find them. |
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You need to use a trigonometric function, SIN, COS, TAN. The trig function of an angle is the ratio for the length of the side given to one of the other sides. So you'd take the trig function of the angle and solve for the unknown side using an algebraic function to solve for x (unknown side) https://www.mathsisfun.com/sine-cosine-tangent.html |
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Patriot
Q-Tard
“We’re surrounded. That simplifies the problem.” - Chesty Puller, USMC
Patriot
Q-Tard
“We’re surrounded. That simplifies the problem.” - Chesty Puller, USMC
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It is not a right triangle so the simple sin cos tan thing for a right triangle can't be used the height and base distance to the opposite is not known. This is what I did that solved it but I don't know if it is real, a formula, or would even work always. a is largest bottom angle. b smaller bottom angle Base ---------------------- x TAN a = height (TAN a / TAN b} +1 |
Set up two equations with the two unknown sides using trig, solve for the height. Tangent could be substituted in one term in [S], but it's an unnecessary step. |
Keep your powder dry, and watch your back trail.
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Thanks for the replies. it will take me a while to go through that to understand all the relationships and make sense to me. Tried all that and could not make it work. Base length is .125". side A on your drawing. I finally found one tan angle1 x tan angle2 H = Base x ------------------------ tan angle1 + tan angle2 |
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Now I will go through each step. The math is correct. Make certain you check whether you are entering degrees, not radians, in the trig functions. Or whether your calculator wants the angles in radians. The first equation is the check. If both sides are not equal, there is an error somewhere. I will add a sketch or two and some notes to the sheet above to help make the calculations more clear. Not my most organized work, I thought I had enough space without starting over:  @j3_ |
Keep your powder dry, and watch your back trail.
I'm watching my back trail.
I'm watching my back trail.