This is based on the old "bridge and flashlight" puzzle.  I thought that those of you who haven't seen it yet might enjoy it.

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Four soldiers have to escape an area that's about to be hit with a B-52 strike.  The only way back to safety is across rickety footbridge that spans a deep gorge.

Here's the tricky part: It's a cloudy, moonless night and the soldiers have only one set of night vision goggles between them.  Even worse, the bridge can't support more than two soldiers at a time.  And, just to make things especially difficult, three of the soldiers are wounded to various degrees which limits the speed at which they can travel.

Adams can cross the bridge in 1 minute.
Brockowicz can cross the bridge in 2 minutes.
Carrasco can cross the bridge in 5 minutes.
Dinkins can cross the bridge in 10 minutes.

If two soldiers cross together, they have to move at the speed of the slower man.

No one can cross the bridge without either using the NVGs or being guided by someone with them.

How can they all get across in 17 minutes before the bombing starts?

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Note: This is a logic problem that doesn't require an "outside the box" solution such as throwing the NVGs across the gorge or having one soldier carry another.

Adams and Brockowitz go over = 2
Adams comes back=1
Carrasco and Dinkins go over=10
Brockowitz comes back=2
Adams and Brockowitz go over = 2

2+1+10+2+2=17.

Right.  The intuitive solution is to use Adams for every trip since he's the fastest, but the key is to have Carrasco and Dinkins go together so there aren't two "slow" trips.

Open up with all they have and hobble across the bridge as fast as possible, laying suppressive fire down as they go.

Failing this, the fastest shoots the slowest and look menacingly at the others...

Adams+Carrasco=6min.
brockowicz+Dinkins=10min

6min+10min=16min/w 1WHOLE min to spare.
Correct?

Umm, which team gets to go across without the NVGs?

Gov thug got it right.