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User Panel
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Posted: 5/6/2004 5:53:59 AM EDT
[#1]
Where's that picture of the bunny with a pancake on its head?
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Posted: 5/6/2004 5:55:17 AM EDT
[#2]
multiply kilocalories by 3086 to get foot-pounds.
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Posted: 5/6/2004 6:45:43 AM EDT
[#3]
I concur with CAMPYBOB...provided you're simply hoisting the weight, in a gravitational field which imparts an acceleration of 9.81 m/s^2, neglecting frictional effect, etc. etc. etc.
If you're sliding it up a hill, you might want to include friction. If you eliminate friction, then it doesn't take any more energy (though you need less power and more time). IBT Fizassist. 
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Posted: 5/6/2004 6:47:50 AM EDT
[#4]
1 kcal is plenty of energy to move a 1000 lb object 1 foot, if u r on a frictionless surface, perfectly flat, and if u neglect air resistance
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Posted: 5/6/2004 6:56:19 AM EDT
[#5]
True - if you're moving it down a hill, then you only need to give it a little nudge (maybe a few dozen calories). |
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Posted: 5/6/2004 1:26:54 PM EDT
[#6]
1 food Calorie is equal to 1000 calories, or 1 kcal. (Note the upper/lowercase).
1 kcal = 4186.7 Joules = 3088 ft*lbf 1000 lbs (at average gravity) raised 12" has 1000 ft*lbf = 1354.9 J potential energy. 1000 ft*lbf / 3088 ft*lbf/1 kcal = 0.324 kcal, or 0.324 cal (NOT food calories). -z |
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Posted: 5/6/2004 5:14:00 PM EDT
[#7]
Problem is harnessing all that energy =(
We're so surrounded by energy yet we don't know how to utilize 99.99% (ok..I totally made up that number) of it. As far as energy crises in the future, I think we'll learn how to harness more and more sources as time goes by, so no big deal wrt the petro edit: sorry for rambling |
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