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Posted: 5/6/2004 4:44:05 AM EST
Does anyone know how many kilocalories it takes to move 1000 lbs one foot?
I understand this might be less than one.

Just curious.
Link Posted: 5/6/2004 4:53:59 AM EST
Where's that picture of the bunny with a pancake on its head?
Link Posted: 5/6/2004 4:55:17 AM EST
Link Posted: 5/6/2004 5:45:43 AM EST
I concur with CAMPYBOB...provided you're simply hoisting the weight, in a gravitational field which imparts an acceleration of 9.81 m/s^2, neglecting frictional effect, etc. etc. etc.

If you're sliding it up a hill, you might want to include friction. If you eliminate friction, then it doesn't take any more energy (though you need less power and more time).

IBT Fizassist.
Link Posted: 5/6/2004 5:47:50 AM EST
1 kcal is plenty of energy to move a 1000 lb object 1 foot, if u r on a frictionless surface, perfectly flat, and if u neglect air resistance

Link Posted: 5/6/2004 5:56:19 AM EST

Originally Posted By Belfry_Express:
1 kcal is plenty of energy to move a 1000 lb object 1 foot, if u r on a frictionless surface, perfectly flat, and if u neglect air resistance




True - if you're moving it down a hill, then you only need to give it a little nudge (maybe a few dozen calories).
Link Posted: 5/6/2004 12:26:54 PM EST
[Last Edit: 5/6/2004 5:19:57 PM EST by Zak-Smith]
1 food Calorie is equal to 1000 calories, or 1 kcal. (Note the upper/lowercase).

1 kcal = 4186.7 Joules = 3088 ft*lbf

1000 lbs (at average gravity) raised 12" has 1000 ft*lbf = 1354.9 J potential energy.

1000 ft*lbf / 3088 ft*lbf/1 kcal = 0.324 kcal, or 0.324 cal (NOT food calories).

-z
Link Posted: 5/6/2004 4:14:00 PM EST
[Last Edit: 5/6/2004 4:14:14 PM EST by jblachly]
Problem is harnessing all that energy =(

We're so surrounded by energy yet we don't know how to utilize 99.99% (ok..I totally made up that number) of it.

As far as energy crises in the future, I think we'll learn how to harness more and more sources as time goes by, so no big deal wrt the petro

edit: sorry for rambling
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