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Posted: 1/3/2012 3:15:02 PM EDT
So my wife and I are trying to help my son who is struggling a touch when we come across this problem. We know the answer as it is multiple choice, but how the hell do we get that answer? Please show your work.

30. Jimmy's Pet Shop has a ratio of 4 dogs to 7 cats. If there are 44 total animals in the shop, how many are cats?

Help me ARFCOM, you're my only hope. Plus, my wife laughed and acted like the Hive couldn't figure this one out.
Link Posted: 1/3/2012 3:17:34 PM EDT
Originally Posted By Stegadeth:
So my wife and I are trying to help my son who is struggling a touch when we come across this problem. We know the answer as it is multiple choice, but how the hell do we get that answer? Please show your work.

30. Jimmy's Pet Shop has a ratio of 4 dogs to 7 cats. If there are 44 total animals in the shop, how many are cats?

Help me ARFCOM, you're my only hope. Plus, my wife laughed and acted like the Hive couldn't figure this one out.


I'd use algebra, but this is only 6th grade math. So...


Out of 11 animals, four are dogs and 7 are cats. There are 44 animals, thus four groups of ll.

4 x 4 =16
4 x 7 = 28
Link Posted: 1/3/2012 3:19:02 PM EDT

Originally Posted By AR4U:
Originally Posted By Stegadeth:
So my wife and I are trying to help my son who is struggling a touch when we come across this problem. We know the answer as it is multiple choice, but how the hell do we get that answer? Please show your work.

30. Jimmy's Pet Shop has a ratio of 4 dogs to 7 cats. If there are 44 total animals in the shop, how many are cats?

Help me ARFCOM, you're my only hope. Plus, my wife laughed and acted like the Hive couldn't figure this one out.


I'd use algebra, but this is only 6th grade math. So...


Out of 11 animals, four are dogs and 7 are cats. There are 44 animals, thus four groups of ll.

4 x 4 =16
4 x 7 = 28

Mind showing the algebra on this as well?
Link Posted: 1/3/2012 3:20:37 PM EDT
[Last Edit: 1/3/2012 3:20:54 PM EDT by KiloBravo]
It's fractions, man ...

4/11 * 44 = Dogs

7/11 * 44 = Cats
Link Posted: 1/3/2012 3:21:07 PM EDT
44=x(4+7) ?

Then solve for X?
Link Posted: 1/3/2012 3:22:15 PM EDT

Originally Posted By KiloBravo:
It's fractions, man ...

4/11 * 44 = Dogs

7/11 * 44 = Cats

Almost got you before the edit.


Link Posted: 1/3/2012 3:24:12 PM EDT
[Last Edit: 1/3/2012 3:26:04 PM EDT by Snips]
4 dogs, 7 cats

dogs = 4:11 ratio
cats = 7:11 ratio

Total # of animals/ratio total * ratio number
44/11 * 4 gives you the dogs
44/11 * 7 gives you the cats
Link Posted: 1/3/2012 3:25:20 PM EDT
4 dogs 7 cats = 11
4 dogs 7 cats = 22
4 dogs 7 cats = 33
4 dogs 7 cats = 44


28 cats :)
Link Posted: 1/3/2012 3:25:39 PM EDT
Go to Khan Academy

He no doubt has a video that talks about fractions and word problems.

Khan Academy
Link Posted: 1/3/2012 3:27:15 PM EDT

Originally Posted By Credge:
44=x(4+7) ?

Then solve for X?

Exactly the method we needed. Thanks all! Trying to figure this crap out when they don't have a book is just tough.
Link Posted: 1/3/2012 3:28:58 PM EDT
Originally Posted By Stegadeth:

Originally Posted By AR4U:
Originally Posted By Stegadeth:
So my wife and I are trying to help my son who is struggling a touch when we come across this problem. We know the answer as it is multiple choice, but how the hell do we get that answer? Please show your work.

30. Jimmy's Pet Shop has a ratio of 4 dogs to 7 cats. If there are 44 total animals in the shop, how many are cats?

Help me ARFCOM, you're my only hope. Plus, my wife laughed and acted like the Hive couldn't figure this one out.


I'd use algebra, but this is only 6th grade math. So...


Out of 11 animals, four are dogs and 7 are cats. There are 44 animals, thus four groups of ll.

4 x 4 =16
4 x 7 = 28

Mind showing the algebra on this as well?


x = number of dogs
7/4 * x = number of cats

44 = x + 7/4 * x
44 =11/4 * x
16 =x = number of dogs
7/4 * 16 = 28 = number of cats


And I noticed that just using the ratios, as another poster did, would have been much faster. Force of habit

Link Posted: 1/3/2012 3:30:17 PM EDT
Originally Posted By Stegadeth:

Originally Posted By Credge:
44=x(4+7) ?

Then solve for X?

Exactly the method we needed. Thanks all! Trying to figure this crap out when they don't have a book is just tough.


KiloBravo's answer is probably what the teacher is looking for.
Link Posted: 1/3/2012 3:31:02 PM EDT
Being a pet shop it is safe to assume that they would only have healthy animals. That is to say that there would be no animals missing legs. (Assumptions and calculated guesses are a key part of mathematics)

So 44 animals with 4 legs each 44x4= 176 legs

now we know the ratio of 4 dogs to 7 cats and math tells us that 4+3=7 so we can say this as 7=3/4

we know there are more cats than dogs so we want to take the 7 and multiply it by the larger number (more cats=larger number)

So now we have 7x4=28 so we have 28 cats

So logic states that if there are 28 cats then the rest must be dogs so we separate the cats from the dogs by further mathematics

44 total animals - 28 cats = 16 dogs.

Basic stuff really....
Link Posted: 1/3/2012 3:33:01 PM EDT
If arfcom ruled the world, we be to mars by now.
Link Posted: 1/3/2012 3:33:43 PM EDT
[Last Edit: 1/3/2012 3:34:55 PM EDT by RedFalconBill]
X(4 + 7) = 44

11X = 44

X = 4

Therefore there are 16 Dogs and 28 Cats
Link Posted: 1/3/2012 3:35:48 PM EDT
Originally Posted By Credge:
44=x(4+7) ?

Then solve for X?


+1.









Impeach Obama for the Good of the College Students.
Link Posted: 1/3/2012 3:36:01 PM EDT

Originally Posted By theBUBBAMANcan:
If arfcom ruled the world, we be to mars by now.

Is that near Uranus......
Link Posted: 1/3/2012 3:39:08 PM EDT
All I know is it isn't a damn opossum.
Link Posted: 1/3/2012 3:41:42 PM EDT
Why doesn't he have a book?
Link Posted: 1/3/2012 3:42:18 PM EDT
Originally Posted By theBUBBAMANcan:
If arfcom ruled the world, we be to mars by now.


That's laughable. While you can ask damn near anything here and almost certainly get a correct answer, that answer will generally be drowned out by a tide of bullshit.
Link Posted: 1/3/2012 3:47:35 PM EDT
Originally Posted By substandard:

Originally Posted By theBUBBAMANcan:
If arfcom ruled the world, we be to mars by now.

Is that near Uranus......


Near the rim....



Posted Via AR15.Com Mobile
Link Posted: 1/3/2012 3:55:12 PM EDT
Check out this link:

http://www.khanacademy.org/search?page_search_query=ratios

They have a lot of great video lessons on a variety of subjects...
Link Posted: 1/3/2012 3:56:17 PM EDT

Originally Posted By AR4U:
Originally Posted By theBUBBAMANcan:
If arfcom ruled the world, we be to mars by now.


That's laughable. While you can ask damn near anything here and almost certainly get a correct answer, that answer will generally be drowned out by a tide of bullshit.

HEY.... bullshit is all some of us have to offer


Link Posted: 1/3/2012 3:58:33 PM EDT
Now express your answer in the form of a question.












What round for 28 cats?
Link Posted: 1/3/2012 3:59:12 PM EDT
"how does this work daddy?"

"uuuuuuuuh... you gotta cheat son, that's what I did"

-Joe Rogan
Link Posted: 1/3/2012 4:01:36 PM EDT

Originally Posted By chicobrownbear:
Now express your answer in the form of a question.

What round for 28 cats?

Brock Lesner?
Link Posted: 1/3/2012 4:05:47 PM EDT
I question is BS unless the shop only sells dogs and cats.
Link Posted: 1/3/2012 4:08:24 PM EDT
[Last Edit: 1/3/2012 4:09:33 PM EDT by Mazeman]
"I question is BS unless the shop only sells dogs and cats. "

I love ARFCOM.
Link Posted: 1/3/2012 4:14:02 PM EDT
Originally Posted By KaiK:
I question is BS unless the shop only sells dogs and cats.


That is a perfectly valid and insightful point which outlines one of the major problems with the way word problems are designed. I've never seen a single pet store that ONLY sells cats and dogs.
Link Posted: 1/3/2012 4:36:25 PM EDT

Originally Posted By AR4U:
Originally Posted By KaiK:
I question is BS unless the shop only sells dogs and cats.


That is a perfectly valid and insightful point which outlines one of the major problems with the way word problems are designed. I've never seen a single pet store that ONLY sells cats and dogs.

Actually it is invalid. It was never stated that they ONLY sold cats and dogs. The problem is just referring to the ratio of cats and dogs at the store.
Link Posted: 1/4/2012 8:25:32 AM EDT
Originally Posted By substandard:

Originally Posted By AR4U:
Originally Posted By KaiK:
I question is BS unless the shop only sells dogs and cats.


That is a perfectly valid and insightful point which outlines one of the major problems with the way word problems are designed. I've never seen a single pet store that ONLY sells cats and dogs.

Actually it is invalid. It was never stated that they ONLY sold cats and dogs. The problem is just referring to the ratio of cats and dogs at the store.


Exactly.

The problem never states that, but it does state that there are 44 total animals in the store. One must know the total number of dogs and cats in order to use the ratios to find the number of cats. That is never explicitly stated. In order to arrive at the "correct" answer, the student has to assume something which is not explicitly stated in the question and runs completely counter to real-life experiences.

Problems like this teach students to "game" the question, not to apply critical thinking skills and math to a physical problem, which is the point of word problems in the first place.
Link Posted: 1/4/2012 2:24:25 PM EDT
Originally Posted By AR4U:
Originally Posted By theBUBBAMANcan:
If arfcom ruled the world, we be to mars by now.


That's laughable. While you can ask damn near anything here and almost certainly get a correct answer, that answer will generally be drowned out by a tide of bullshit.


Just reference the "plane on a treadmill" and ".9bar = 1 threads

Link Posted: 1/4/2012 3:31:24 PM EDT
Originally Posted By Stegadeth:
30. Jimmy's Pet Shop has a ratio of 4 dogs to 7 cats. If there are 44 total animals in the shop, how many are cats?
[div]


d/c = 4/7

d+c = 44

d = 4/7*c

4/7*c + c = 44

11/7*c = 44

c = 44/11*7

C = 28.
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