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Posted: 4/10/2002 7:50:13 AM EDT
I was reading my Army sniper book yesterday, and was reading about a certain formula, talking about windage.

R*100+ Wind/constant R=range, and wind is the speed+ position you are to it.

Constant is the bullet=20 was given for the .308 bullet used by the amry.

Basically the formula gave you what you should do for adjustment for wind.
did I make sense?

Now, how do you come up with the constant?

Say for a 50 cal round?
c-rock
Link Posted: 4/10/2002 11:25:32 AM EDT
That's a tough one. I have read this somewhere before. Let me check my Tactical shooter and Precision shooter mags. I have it somewhere.

Craig
Link Posted: 4/10/2002 6:26:39 PM EDT
Ok,
I got the info from sniper Training and employment book. TC 23-14
Army Manual.

I stand corrected, this is the formula.
(R 100) X V / constant

R is the range in 100 yrds'

V is the velocity of the wind in miles per hour
half value winds, divide the answer by two.
Meaning if the wind is coming in at 45 degrees from your shooting position.

The constant is what throws me!
This is what the book says- M118 special ball round is 20, constant may not remain correct if other ammunition is used
Changes in bullet weight and velocity affect performance characterists.
Example- Wind is 9 o'clock at 5 mph
range is 800 mm

So 8 X 5/20= 2moa adustment to the left side for the shot.

Now, I want to know what to use for a 50 cal rifle.

Heck, I was thinking of painting that onto the side of the rifle, so I have a cliff note on it!

Also the formula for how to lead a moving target!
Figure it would be a neat converstation peice to have when people see it.

Anyways, this question has been on my mind all day.
Thanks
c-rock
Link Posted: 4/10/2002 6:59:02 PM EDT
I thought it was in 'The Ultimate Sniper'. The closest I can find is on page 294. Here he says to use 15 as the constant out to 500 yards, then reduce the constant by one for each hundred yards past that. So use 14 for 600, 13 for 700, etc. He refers to it as a Marine method.
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