Run me through it...
At any given point the sum of the lift is equal to the weight of the helicopter, requiring the same vector for identical bank angles. So, the total power required for the main rotor would be equal, in either direction (assuming equal bank turns). (I'm assuming the same relative airflow over the blade...but might be wrong?) Does the retreating blade being on the high or low side make a difference? (Additionally, are we factoring the vector of the tail-rotor's lift component at the bank angle? If the bank tilts the anti-torque up, then there is an additional lift component from the tail-rotor)
If it is in trim, the anti-torque required should be directly proportional to the total power required...which would be the same.
Now, rolling in and out of the turn, the transient torque will be greater rolling toward the retreating blade side...