So we have a bridge string spacing of 2.1 inches which gives us an arc length of 2.1003, which works out to an angle for the whole bridge of 16.045 degrees when the radius is 15 inches. 15 inches was the stock fretboard radius the Kahler Spyder bridge was built with, according to the guy who answered the phone at Kahler.
So, per the diagram, we have the angle to get the included angle 8.0225 degrees - the cosine of which is 0.99021334. So the formula given calculates that the distance to a tangent line, raw, is 0.1467999 inches, for the high and low E strings. We will have to adjust that a little, more on that later.
We have 6 strings, equally spaced, which divides our total bridge arc into 5 equal arcs. We now need to calculate the included angle for the A and B strings, which will be half of 3/5ths of that of the total bridge, or 4.8135 degrees/
Our formula cranks out 0.0529032 inches, raw.
BUT our center two strings are also a distance from the tangent. However, we need to "Zero" our saddles heights by subtracting this distance from the other calculations! The distance from the tangent involves a central angle of half of 1/5 of 16.045 degrees, which is an easy to figure 0.0529032 degrees. The formula gives us a distance to the tangent of : 0.00000645 inches.
So our actual saddle height for the low and high E strings is 0.14679345 inches.
The A and D strings work out to 0.05289675. The effect of zeroing out for the center saddle height is very small. Let's see how things work out for a 17 inch radius!