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Quoted:
P.S. The good thing of fluorescent fixtures is not only the lower wattage. You screw the power company out of more money, through inductive reactance of the transformer in the ballast. [}:D]
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For those of you familiar with complex power......
The power company charges on power (Watts)/time (P/t) or "true power", that is simply:
P = (I^2)R, VI, or (V^2)/R
where: [i]* ^2 = squared[/i]
Since in the US, power is supplied via a 60Hz sinusoid and the ballast load is inductive, it has a reactive impedance "Z" which is dependant on the frequency (60Hz). Now enters the complex J component in the load which the power company ignores in the power math. This is the apparent power; "S" The units are; VA or Volts-Amperes.
Just substitue the the impedance "Z" for the real resistance "R" in the above power equations.
There is also VAR reactive power.........
[:D]
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I just wanted to add in layman terms, blah blah blah, blah blah.
This theory can be applied to motor loads also. I have reference material in this room.........but I don't want to boar[:)] people or waste my time.[;)]