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Posted: 8/14/2013 7:46:14 PM EDT
Can someone help me with this?  If I have 2 inch shaft turning about 120 rpm and I put a 4 inch wheel against the shaft, what is the rpm of the wheel?  There are no gears involved just the shaft pressed against the wheel to turn it.
Link Posted: 8/14/2013 7:51:04 PM EDT
[#1]
60 rpm
Link Posted: 8/14/2013 9:55:47 PM EDT
[#2]

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Quoted:


60 rpm
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Yup.  The circumference of the 4" wheel is double that of the 2" shaft, so it turns half the speed.  



 
Link Posted: 8/15/2013 5:26:07 PM EDT
[#3]
In a case like this, you can use conservation of angular momentum.

r1w1 = r2w2  where r1 and r2 are the respective radii, and w1 and w2 are omega 1 and omega 2, the angular frequency of each shaft.

2 (120) = 4 w2 ---> w2 = 60

60 rpm
Link Posted: 8/15/2013 9:06:19 PM EDT
[#4]
Discussion ForumsJump to Quoted PostQuote History
Quoted:
In a case like this, you can use conservation of angular momentum.

r1w1 = r2w2  where r1 and r2 are the respective radii, and w1 and w2 are omega 1 and omega 2, the angular frequency of each shaft.

2 (120) = 4 w2 ---> w2 = 60

60 rpm
View Quote


Thanks for the answer.
Link Posted: 8/16/2013 9:55:24 AM EDT
[#5]
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Quoted:


Thanks for the answer.
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View All Quotes
Discussion ForumsJump to Quoted PostQuote History
Quoted:
Quoted:
In a case like this, you can use conservation of angular momentum.

r1w1 = r2w2  where r1 and r2 are the respective radii, and w1 and w2 are omega 1 and omega 2, the angular frequency of each shaft.

2 (120) = 4 w2 ---> w2 = 60

60 rpm


Thanks for the answer.

I feel slighted. You didn't ask for an explanation just how many RPM
Link Posted: 8/16/2013 8:55:01 PM EDT
[#6]
Well, if you really want to get technical, it actually has nothing to do with conservation of angular momentum.  The two are in direct contact; they're acting like gears.  It's a simple ratio of circumferences that determines the speed.  Angular momentum is an expression of the intertia of a rotating mass - i.e. the spinning skater pulls in their arms and spins faster because they reduced their angular momentum and energy must be conserved, so they speed up.
Link Posted: 8/16/2013 10:28:53 PM EDT
[#7]
Discussion ForumsJump to Quoted PostQuote History
Quoted:
Well, if you really want to get technical, it actually has nothing to do with conservation of angular momentum.  The two are in direct contact; they're acting like gears.  It's a simple ratio of circumferences that determines the speed.  Angular momentum is an expression of the intertia of a rotating mass - i.e. the spinning skater pulls in their arms and spins faster because they reduced their angular momentum and energy must be conserved, so they speed up.
View Quote


I had the wrong term, right formula.

When the skater pulls their arms in, their angular momentum is not reduced. Their moment of inertia is reduced, so their angular velocity, omega, must increase. Angular momentum is conserved in that case.
Link Posted: 8/19/2013 1:41:53 PM EDT
[#8]
This type of power feed is usually used to provide a slip point 9clutch type function) in a system and make sure the load on th ewhel does not get larger than desired.

Gears do not slip without spring engagement that allows one side to pop out of engagement.

Under load the wheel will slip against the shaft.
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